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Butan-1-ol burns in oxygen according to the following equation - HSC - SSCE Chemistry - Question 4 - 2013 - Paper 1
Question 4
Butan-1-ol burns in oxygen according to the following equation. C₄H₁₀O(l) + 6O₂(g) → 4CO₂(g) + 5H₂O(l) How many moles of carbon dioxide would form if two moles of ... show full transcript
Worked Solution & Example Answer:Butan-1-ol burns in oxygen according to the following equation - HSC - SSCE Chemistry - Question 4 - 2013 - Paper 1
Step 1
How many moles of carbon dioxide would form if two moles of butan-1-ol were burnt in excess oxygen?
Answer
According to the balanced chemical equation:
From the equation, it is observed that 1 mole of butan-1-ol produces 4 moles of carbon dioxide. Therefore, if 2 moles of butan-1-ol are burnt in excess oxygen:
- Moles of carbon dioxide produced = 2 moles of butan-1-ol × 4 moles CO₂/mole butan-1-ol
- Moles of carbon dioxide produced = 8 moles
Thus, the answer is (C) 8.