Photo AI
Question 28
A galvanic cell has been constructed as shown in the diagram. X metal (anode) Colourless solution 1.0 mol L$^{-1}$ nitrate salt solution of X Cu metal (cathode) B... show full transcript
Step 1
Answer
As the reaction proceeds, the blue solution in the copper half-cell becomes lighter in color. This color change occurs because copper ions ( ext{Cu}^{2+}) are reduced at the cathode as copper metal is deposited. The decrease in concentration of copper ions in the solution leads to the lighter blue color observed.
Step 2
Answer
Metal X is aluminum (Al). This is determined using the standard reduction potentials. Given that the overall standard cell potential is 2.02 V, we can analyze the potential of aluminum used as the anode:
E = E + E
Given E for copper is 0.34 V, we can rearrange:
2.02 V = E + 0.34 V
Thus, E = 2.02 V - 0.34 V = 1.68 V. The standard potential for aluminum is approximately -1.66 V. Therefore, the identification of aluminum is consistent with the calculated standard potentials.
Report Improved Results
Recommend to friends
Students Supported
Questions answered