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A bottle labelled ‘propanol’ contains one of two isomers of propanol - HSC - SSCE Chemistry - Question 27 - 2022 - Paper 1

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A bottle labelled ‘propanol’ contains one of two isomers of propanol. (a) Draw the TWO isomers of propanol. (b) Describe how 13C NMR spectroscopy might be used to ... show full transcript

Worked Solution & Example Answer:A bottle labelled ‘propanol’ contains one of two isomers of propanol - HSC - SSCE Chemistry - Question 27 - 2022 - Paper 1

Step 1

Draw the TWO isomers of propanol.

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Answer

The two isomers of propanol are:

  1. Propan-1-ol (n-propanol), with the hydroxyl group (-OH) on the first carbon:

    H3C - CH2 - CH2 - OH

  2. Propan-2-ol (isopropanol), with the hydroxyl group (-OH) on the second carbon:

    H3C - CH(OH) - CH3

Step 2

Describe how 13C NMR spectroscopy might be used to identify which isomer is in the bottle.

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Answer

The use of 13C NMR spectroscopy can help identify the isomer based on the number of distinct carbon environments in the molecule.

  • Propan-1-ol will produce 3 signals because it has three different carbon environments.
  • Propan-2-ol will produce 2 signals since it has a more symmetrical structure.

By analyzing the spectrum, if the bottle produces 2 signals, it indicates propan-2-ol, while 3 signals correspond to propan-1-ol.

Step 3

Write equations to represent the oxidation reactions of the two isomers. Include reaction conditions.

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Answer

  1. Oxidation of Propan-1-ol (Propan-1-ol to Propanoic Acid):

    CH3CH2CH2OH + [O] → CH3CH2COOH

    Reaction conditions: Acidified potassium dichromate (H+/K2Cr2O7)

  2. Oxidation of Propan-2-ol (Propan-2-ol to Acetone):

CH3CHOHCH3 + [O] → CH3COCH3

Reaction conditions: Acidified potassium dichromate (H+/K2Cr2O7) or another suitable oxidizing agent.

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