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The molar heat of combustion of ethanol is 1367 kJ mol<sup>−1</sup> - HSC - SSCE Chemistry - Question 10 - 2008 - Paper 1

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The molar heat of combustion of ethanol is 1367 kJ mol<sup>−1</sup>. What quantity of ethanol must be combusted to raise the temperature of 1.0 kg water from 50°C t... show full transcript

Worked Solution & Example Answer:The molar heat of combustion of ethanol is 1367 kJ mol<sup>−1</sup> - HSC - SSCE Chemistry - Question 10 - 2008 - Paper 1

Step 1

What quantity of ethanol must be combusted to raise the temperature of 1.0 kg water from 50°C to boiling point at sea level?

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Answer

To calculate the amount of ethanol required, we first need to find the heat energy required to raise the temperature of the water.

  1. Calculate the heat energy needed (Q): The required temperature change for water is:

    100 °C - 50 °C = 50 °C

    The heat energy needed can be calculated using the formula:

    Q=mchetaQ = mc heta

    Where:

    • m = mass of the water = 1.0 kg
    • c = specific heat capacity of water = 4.18 kJ/(kg·°C)
    • θ = change in temperature = 50 °C

    Inserting values:

    Q=1.0extkgimes4.18extkJ/(kg°C)imes50ext°C=209extkJQ = 1.0 ext{ kg} imes 4.18 ext{ kJ/(kg·°C)} imes 50 ext{ °C} = 209 ext{ kJ}

  2. Determine moles of ethanol required: With the molar heat of combustion of ethanol being 1367 kJ/mol, the number of moles needed to produce 209 kJ is:

    ext{moles} = rac{Q}{ ext{molar heat}} = rac{209 ext{ kJ}}{1367 ext{ kJ/mol}} ext{ moles} ≈ 0.153 ext{ mol}

  3. Calculate mass of ethanol required: The molar mass of ethanol (C₂H₅OH) is approximately 46 g/mol. Therefore, the mass of ethanol required is:

    extmass=extmolesimesextmolarmass=0.153extmolimes46extg/mol7.0extg ext{mass} = ext{moles} imes ext{molar mass} = 0.153 ext{ mol} imes 46 ext{ g/mol} ≈ 7.0 ext{ g}

Thus, the quantity of ethanol required is approximately 7.0 g.

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