Sodium chloride dissolves in water according to the following equation - HSC - SSCE Chemistry - Question 4 - 2023 - Paper 1

The solubility product constant (Ksp) is calculated using the concentration of the ions in the saturated solution. For sodium chloride (NaCl), the dissociation can be represented as follows:

$K_{sp} = [Na^+][Cl^-]$

Given that both ions have the same concentration of 6.13 mol L⁻¹:

$K_{sp} = (6.13)(6.13) = 6.13^2$

Calculating this:

$K_{sp} = 37.4969$

Rounding gives approximately 37.5, therefore the correct answer is D: 37.6.