Three separate colourless solutions each contain one cation, Na<sup>+</sup>, Pb<sup>2+</sup> or Ca<sup>2+</sup> - HSC - SSCE Chemistry - Question 8 - 2009 - Paper 1
Question 8
Three separate colourless solutions each contain one cation, Na<sup>+</sup>, Pb<sup>2+</sup> or Ca<sup>2+</sup>.
Which of the following would be an appropriate reage... show full transcript
Worked Solution & Example Answer:Three separate colourless solutions each contain one cation, Na<sup>+</sup>, Pb<sup>2+</sup> or Ca<sup>2+</sup> - HSC - SSCE Chemistry - Question 8 - 2009 - Paper 1
Step 1
Identify the cations in the solutions
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Answer
The given cations are Na<sup>+</sup>, Pb<sup>2+</sup>, and Ca<sup>2+</sup>. To distinguish the solution containing Pb<sup>2+</sup> from the others, we need a reagent that specifically reacts with lead ions.
Step 2
Evaluate the reagents provided
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We need to consider each reagent's response with Pb<sup>2+</sup>:
KI: Reaction produces a precipitate of PbI<sub>2</sub> indicating the presence of lead ions.
K<sub>2</sub>CO<sub>3</sub>: Produces a carbonate precipitate but not specific to lead.
K<sub>2</sub>PO<sub>4</sub>: Forms a precipitate of Pb<sub>3</sub>(PO<sub>4</sub>)<sub>2</sub> but may also react with other metals.
AgNO<sub>3</sub>: Produces a white precipitate of PbCl<sub>2</sub> upon reaction with Pb<sup>2+</sup>, but it is not as specific.
Among these, KI is the best option as the precipitate can be obviously identified as lead iodide (PbI<sub>2</sub>).
Step 3
Choose the best reagent for the identification
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Answer
Given the analysis above, the most appropriate reagent to unambiguously identify the solution containing Pb<sup>2+</sup> is (A) KI.