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An indicator is placed in water - HSC - SSCE Chemistry - Question 25 - 2013 - Paper 1

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An indicator is placed in water. The resulting solution contains the green ion, Ind<sup>-</sup>, and the red molecule, HInd. Explain why this solution can be used a... show full transcript

Worked Solution & Example Answer:An indicator is placed in water - HSC - SSCE Chemistry - Question 25 - 2013 - Paper 1

Step 1

Explain why this solution can be used as an indicator.

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Answer

An indicator functions by changing color when there is a shift in equilibrium, which occurs in response to pH changes. The solution containing Ind<sup>-</sup> (green) and HInd (red) demonstrates this equilibrium behavior:

extHInd(aq)+extH2extO(l)Ind(aq)+extH3extO(aq)+ ext{HInd}_{(aq)} + ext{H}_2 ext{O}_{(l)} \rightleftharpoons \text{Ind}^-{(aq)} + ext{H}_3 ext{O}^+_{(aq)}

When an acid is added to the solution, the concentration of H<sub>3</sub>O<sup>+</sup> increases, shifting the equilibrium to the left and favoring the formation of HInd, which is red. Conversely, when a base is added, the concentration of H<sub>3</sub>O<sup>+</sup> decreases, shifting equilibrium to the right, resulting in the green color of Ind<sup>-</sup>. This characteristic color change enables the solution to act as an effective indicator.

Step 2

Include a suitable chemical equation that uses Ind<sup>-</sup> and HInd.

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Answer

The chemical equation representing the equilibrium is as follows:

extHInd(aq)+extH2extO(l)Ind(aq)+extH3extO(aq)+ ext{HInd}_{(aq)} + ext{H}_2 ext{O}_{(l)} \rightleftharpoons \text{Ind}^-{(aq)} + ext{H}_3 ext{O}^+_{(aq)}

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