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Butan-1-ol burns in oxygen according to the following equation - HSC - SSCE Chemistry - Question 4 - 2013 - Paper 1
Question 4
Butan-1-ol burns in oxygen according to the following equation. C₄H₉OH(l) + 6O₂(g) → 4CO₂(g) + 5H₂O(l) How many moles of carbon dioxide would form if two moles of ... show full transcript
Worked Solution & Example Answer:Butan-1-ol burns in oxygen according to the following equation - HSC - SSCE Chemistry - Question 4 - 2013 - Paper 1
Step 1
How many moles of carbon dioxide would form if two moles of butan-1-ol were burnt in excess oxygen?
Answer
From the balanced chemical equation, we see that 1 mole of butan-1-ol produces 4 moles of carbon dioxide.
Given that 2 moles of butan-1-ol are being burned, we can apply a simple ratio:
If 1 mole of butan-1-ol → 4 moles of CO₂, then:
2 ext{ moles of butan-1-ol} imes rac{4 ext{ moles of CO₂}}{1 ext{ mole of butan-1-ol}} = 8 ext{ moles of CO₂}Thus, when 2 moles of butan-1-ol are burnt, 8 moles of carbon dioxide are formed.