In a fermentation experiment 6.50 g of glucose was completely converted to ethanol and carbon dioxide - HSC - SSCE Chemistry - Question 13 - 2009 - Paper 1

From the fermentation reaction:

$\text{C}_6\text{H}_{12}\text{O}_6 \rightarrow 2 \text{C}_2\text{H}_5\text{OH} + 2 \text{CO}_2$

Each mole of glucose produces 2 moles of carbon dioxide. Therefore, the moles of carbon dioxide produced is:

$2 \times 0.0361 \approx 0.0722 \text{ moles}$

To find the mass of carbon dioxide (CO₂), we use the formula:

$m = n \times M$

Where:

• n = moles of carbon dioxide = 0.0722 moles
• M = molar mass of CO₂ = 44.01 g/mol

Thus:

$m = 0.0722 \times 44.01 \approx 3.18 \text{ g}$

The mass of carbon dioxide produced is approximately 3.18 g, which corresponds to option (B).