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A student set up the following experiment to model a process and observed the colour change of the crystals - HSC - SSCE Chemistry - Question 33 - 2011 - Paper 1

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A student set up the following experiment to model a process and observed the colour change of the crystals. Copper(II) sulfate pentahydrate crystals in watch glass... show full transcript

Worked Solution & Example Answer:A student set up the following experiment to model a process and observed the colour change of the crystals - HSC - SSCE Chemistry - Question 33 - 2011 - Paper 1

Step 1

Identify liquid X and explain the colour change of the crystals. Include a chemical equation in your answer.

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Answer

Liquid X can be identified as water (H₂O). When Copper(II) sulfate pentahydrate (CuSO₄·5H₂O) is exposed to water, it undergoes hydration. The colour change of the crystals from blue to a lighter blue occurs because the hydrated form of Copper(II) sulfate absorbs water, forming more hydrated ions. The chemical equation for this process is:

CuSO45H2O(s)+H2O(l)Cu2+(aq)+SO42(aq)+5H2O(l)CuSO₄·5H₂O (s) + H₂O (l) \rightleftharpoons Cu^{2+} (aq) + SO₄^{2-} (aq) + 5H₂O (l)

Step 2

Why are the large volumes of CO₂(g) produced during the Solvay process of little environmental concern? Include chemical equations in your answer.

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The large volumes of CO₂(g) produced during the Solvay process are of little environmental concern due to the relatively small contribution of industrial processes to overall greenhouse gas emissions. Additionally, the CO₂ produced can be largely recycled and utilized in other chemical processes.

The chemical equations demonstrating the production of CO₂ in the Solvay process are:

  1. Formation of sodium bicarbonate: NH4Cl(aq)+Na2CO3(s)2NaHCO3(aq)+NH3(g)NH₄Cl (aq) + Na₂CO₃ (s) \rightarrow 2NaHCO₃ (aq) + NH₃ (g)
  2. Decomposition of sodium bicarbonate: 2NaHCO3(s)Na2CO3(s)+CO2(g)+H2O(g)2NaHCO₃ (s) \rightarrow Na₂CO₃ (s) + CO₂ (g) + H₂O (g)

Step 3

Calculate the mass of calcium chloride produced per tonne of sodium chloride used in the Solvay process.

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Answer

To calculate the mass of calcium chloride produced from sodium chloride in the Solvay process, we can use the stoichiometric equation involved in the process. The balanced equation is:

CaCO3(s)+2NaCl(aq)CaCl2(aq)+Na2CO3(s)CaCO₃ (s) + 2NaCl (aq) \rightarrow CaCl₂ (aq) + Na₂CO₃ (s)

From the equation, 1 mole of CaCl₂ is produced from 2 moles of NaCl. The molar mass of NaCl is approximately 58.5 g/mol, and for CaCl₂ it is approximately 110.98 g/mol. For 1 tonne (1000 kg) of NaCl, we have:

Moles of NaCl = 1000 kg / (58.5 g/mol) = 17114.53 mol

Since 2 moles of NaCl yield 1 mole of CaCl₂, we have:

Moles of CaCl₂ = 17114.53 mol / 2 = 8557.27 mol

Mass of CaCl₂ = 8557.27 mol × 110.98 g/mol = 949,933.48 g or approximately 949.93 kg.

Step 4

Account for the observations at the anode and cathode. Include relevant chemical equations in your answer.

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At the anode (positive electrode), oxidation occurs, producing oxygen gas, which causes bubbles. The relevant half-equation is:

2H2O(l)O2(g)+4H+(aq)+4e2H₂O (l) \rightarrow O₂ (g) + 4H^+ (aq) + 4e^-

At the cathode (negative electrode), reduction occurs. The hydrogen ions gain electrons to form hydrogen gas, leading to the observed bubbles. The relevant half-equation is:

2H+(aq)+2eH2(g)2H^+ (aq) + 2e^- \rightarrow H₂ (g)

The litmus paper at the anode turns red indicating acidic conditions due to the generation of H⁺ ions, whereas the litmus paper at the cathode turns blue indicating alkaline conditions due to the production of hydroxide ions (OH⁻).

Step 5

What is the difference between the electrolytic cell described above and a galvanic cell, in terms of energy requirements?

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Answer

An electrolytic cell requires an external source of energy to drive the chemical reactions, as it involves non-spontaneous processes. In contrast, a galvanic cell generates electrical energy from spontaneous chemical reactions. In a galvanic cell, the chemical energy produced from the redox reactions is converted into electrical energy, allowing it to operate without an external power source.

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