What are the reactants used to make this compound?
O
CH₃CH₂CH₂ – C – O – CH₂CH₂CH₃
(A) Butan-1-ol and butanoic acid
(B) Butan-1-ol and propanoic acid
(C) Propan-1-ol and butanoic acid
(D) Propan-1-ol and propanoic acid - HSC - SSCE Chemistry - Question 9 - 2015 - Paper 1
Question 9
What are the reactants used to make this compound?
O
CH₃CH₂CH₂ – C – O – CH₂CH₂CH₃
(A) Butan-1-ol and butanoic acid
(B) Butan-1-ol and propanoic acid
... show full transcript
Worked Solution & Example Answer:What are the reactants used to make this compound?
O
CH₃CH₂CH₂ – C – O – CH₂CH₂CH₃
(A) Butan-1-ol and butanoic acid
(B) Butan-1-ol and propanoic acid
(C) Propan-1-ol and butanoic acid
(D) Propan-1-ol and propanoic acid - HSC - SSCE Chemistry - Question 9 - 2015 - Paper 1
Step 1
Identify the structure
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Answer
The compound shown in the question is an ester, indicated by the presence of the C=O (carbonyl) and the -O- (ether) groups. The structure suggests a reaction involving an alcohol and a carboxylic acid.
Step 2
Determine the reactants
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Answer
To create the ester, we need to identify the alcohol and the acid that correspond to the compound. The alkyl groups on either side of the ester linkage suggest the following:
The left side (butyl group) indicates Butan-1-ol is likely involved.
The right side, represented by -O-CH₂CH₂CH₃ suggests propanoic acid (as it will provide the necessary two carbon atoms).
Step 3
Choose the correct option
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Answer
Based on the analysis, the reactants Butan-1-ol and propanoic acid are needed to produce the ester compound shown. Therefore, the correct answer is (B) Butan-1-ol and propanoic acid.
