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In a fermentation experiment 6.50 g of glucose was completely converted to ethanol and carbon dioxide - HSC - SSCE Chemistry - Question 13 - 2009 - Paper 1

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In a fermentation experiment 6.50 g of glucose was completely converted to ethanol and carbon dioxide. What is the mass of carbon dioxide produced?

Worked Solution & Example Answer:In a fermentation experiment 6.50 g of glucose was completely converted to ethanol and carbon dioxide - HSC - SSCE Chemistry - Question 13 - 2009 - Paper 1

Step 1

Calculate the molar mass of glucose (C₆H₁₂O₆)

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Answer

To begin, we find the molar mass of glucose. The atomic masses are approximately:

  • Carbon (C): 12.01 g/mol
  • Hydrogen (H): 1.008 g/mol
  • Oxygen (O): 16.00 g/mol

The molar mass of glucose is calculated as follows:

extMolarmassofC6H12O6=(6imes12.01)+(12imes1.008)+(6imes16.00)=180.18extg/mol ext{Molar mass of C₆H₁₂O₆} = (6 imes 12.01) + (12 imes 1.008) + (6 imes 16.00) = 180.18 ext{ g/mol}

Step 2

Convert mass of glucose to moles

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Answer

Using the formula:

ext{moles} = rac{ ext{mass}}{ ext{molar mass}}

Substituting the values, we get:

ext{moles of glucose} ightarrow 0.0361 ext{ mol}$$

Step 3

Determine the moles of carbon dioxide produced

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Answer

From the fermentation balanced equation:

ightarrow 2 ext{C₂H₅OH} + 2 ext{CO₂}$$ This shows that 1 mole of glucose produces 2 moles of carbon dioxide. Thus, the moles of carbon dioxide produced is: $$ ext{moles of CO₂} = 0.0361 ext{ mol} imes 2 = 0.0722 ext{ mol}$$

Step 4

Calculate the mass of carbon dioxide produced

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Answer

Finally, using the molar mass of carbon dioxide (CO₂), which is approximately 44.01 g/mol:

extmassofCO2=extmolesimesextmolarmass ext{mass of CO₂} = ext{moles} imes ext{molar mass}

Substituting the values:

ext{mass of CO₂} ightarrow 3.18 ext{ g}$$

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