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Glucose (C6H12O6) is a monomer that can form naturally occurring polymers - HSC - SSCE Chemistry - Question 6 - 2006 - Paper 1

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Glucose (C6H12O6) is a monomer that can form naturally occurring polymers. The approximate atomic weights for the elements which make up glucose are shown in the ta... show full transcript

Worked Solution & Example Answer:Glucose (C6H12O6) is a monomer that can form naturally occurring polymers - HSC - SSCE Chemistry - Question 6 - 2006 - Paper 1

Step 1

Calculate the molecular weight of one glucose monomer

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Answer

To find the molecular weight of one glucose monomer (C6H12O6), we use the atomic weights from the table:

  • Carbon: 6 atoms × 12 = 72
  • Hydrogen: 12 atoms × 1 = 12
  • Oxygen: 6 atoms × 16 = 96

Thus, the molecular weight of one glucose monomer is:

72+12+96=18072 + 12 + 96 = 180

Step 2

Calculate the molecular weight of 5 glucose monomers

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Now, we multiply the molecular weight of one glucose monomer by the number of monomers:

180imes5=900180 imes 5 = 900

However, in forming a polymer, two hydrogen and one oxygen atom are released for each glycosidic bond formed. In a polymer made from 5 monomers, there are 4 bonds formed, resulting in:

  • Hydrogen: 12 - 4 = 8
  • Oxygen: 6 - 1 = 5

Thus, the adjusted molecular weight of the polymer:

  • Carbon: 6 × 12 = 72
  • Hydrogen: 8 × 1 = 8
  • Oxygen: 5 × 16 = 80

Therefore, the total adjusted molecular weight is:

72+8+80=16072 + 8 + 80 = 160

So, we calculate the final weight for 5 monomers:

180imes54imes18=90072=828180 imes 5 - 4 imes 18 = 900 - 72 = 828

Step 3

Final Answer

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Answer

Thus, the approximate molecular weight of a polymer made from 5 glucose monomers is 828.

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