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Sodium reacts with water to give hydrogen gas and sodium hydroxide solution - HSC - SSCE Chemistry - Question 14 - 2013 - Paper 1

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Sodium reacts with water to give hydrogen gas and sodium hydroxide solution. What volume of gas would be produced from the reaction of 22.99 g of sodium at 25°C and... show full transcript

Worked Solution & Example Answer:Sodium reacts with water to give hydrogen gas and sodium hydroxide solution - HSC - SSCE Chemistry - Question 14 - 2013 - Paper 1

Step 1

Calculate the moles of sodium (Na)

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Answer

To find the number of moles of sodium, use the molar mass of sodium, which is approximately 22.99 g/mol:

n=mM=22.99g22.99g/mol=1moln = \frac{m}{M} = \frac{22.99\,g}{22.99\,g/mol} = 1\,mol

Step 2

Determine the volume of hydrogen gas produced

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Answer

From the balanced chemical equation for the reaction of sodium with water:

2Na+2H2O2NaOH+H22\,Na + 2\,H_2O \rightarrow 2\,NaOH + H_2

According to the equation, 2 moles of sodium produce 1 mole of hydrogen gas. Therefore, 1 mole of sodium will produce:

121mol=0.5molH2\frac{1}{2} \cdot 1\,mol = 0.5\,mol \, H_2

Step 3

Apply the Ideal Gas Law to find the volume

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Using the Ideal Gas Law, which states:

PV=nRTPV = nRT

Where:

  • P is pressure (100 kPa = 100,000 Pa)
  • V is volume (in m³)
  • n is the number of moles (0.5 mol)
  • R is the gas constant (8.314 J/(mol·K))
  • T is temperature (25°C = 298 K)

Rearranging for V gives:

V=nRTP=0.5mol8.314J/(molK)298K100,000PaV = \frac{nRT}{P} = \frac{0.5\,mol \cdot 8.314\,J/(mol\cdot K) \cdot 298\,K}{100,000\,Pa}

Calculating this:

V=0.58.314298100,0000.0124m3V = \frac{0.5 \cdot 8.314 \cdot 298}{100,000} \approx 0.0124\,m^3

Converting to liters (1 m³ = 1000 L):

V12.40LV \approx 12.40\,L

Step 4

Select the correct answer from the options

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Answer

The calculated volume of hydrogen gas produced from the reaction is approximately 12.40 L, thus the answer is (B) 12.40 L.

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