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Which inequality gives the domain of $y = \sqrt{2x - 3}$? A - HSC - SSCE Mathematics Advanced - Question 3 - 2020 - Paper 1

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Which inequality gives the domain of $y = \sqrt{2x - 3}$? A. $x \leq \frac{3}{2}$ B. $x \geq \frac{3}{2}$ C. $x < \frac{3}{2}$ D. $x > \frac{3}{2}$

Worked Solution & Example Answer:Which inequality gives the domain of $y = \sqrt{2x - 3}$? A - HSC - SSCE Mathematics Advanced - Question 3 - 2020 - Paper 1

Step 1

Determine the domain restriction

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Answer

To find the domain of the function y=2x3y = \sqrt{2x - 3}, we need to ensure that the expression inside the square root is non-negative. This leads us to the inequality:

2x302x - 3 \geq 0

Step 2

Solve the inequality

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Answer

Solving the inequality gives:

2x3    x322x \geq 3 \implies x \geq \frac{3}{2}

Step 3

Choose the correct answer

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Answer

Based on the solution, the correct inequality representing the domain of the function is:

B. x32x \geq \frac{3}{2}

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