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Let $f(x)$ be any function with domain all real numbers - HSC - SSCE Mathematics Advanced - Question 9 - 2023 - Paper 1

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Let $f(x)$ be any function with domain all real numbers. Which of the following is an even function, regardless of the choice of $f(x)$? A. $2f(x)$ B. $f(f(x))$ C.... show full transcript

Worked Solution & Example Answer:Let $f(x)$ be any function with domain all real numbers - HSC - SSCE Mathematics Advanced - Question 9 - 2023 - Paper 1

Step 1

A. $2f(x)$

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Answer

An even function satisfies the condition f(x)=f(x)f(-x) = f(x). Here, 2f(x)2f(x) does not necessarily satisfy this condition because if f(x)f(x) is odd, then 2f(x)=2f(x)2f(-x) = -2f(x), which violates the requirement.

Step 2

B. $f(f(x))$

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Answer

The function f(f(x))f(f(x)) does not generally satisfy the even function property. If f(x)f(x) is odd, then f(f(x))f(f(-x)) may not equal f(f(x))f(f(x)).

Step 3

C. $(f(-x))^2$

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Answer

The expression (f(x))2(f(-x))^2 is always non-negative and satisfies the condition of being even since (x)2=x2(-x)^2 = x^2. Hence, it is an even function.

Step 4

D. $f(x)f(-x)$

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Answer

The product f(x)f(x)f(x)f(-x) is also always even. This is because:

f(x)f((x))=f(x)f(x)f(-x)f(-(-x)) = f(-x)f(x)

Thus, this expression satisfies the condition for being an even function.

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