Photo AI

The table shows the probability distribution of a discrete random variable - HSC - SSCE Mathematics Advanced - Question 12 - 2023 - Paper 1

Question icon

Question 12

The-table-shows-the-probability-distribution-of-a-discrete-random-variable-HSC-SSCE Mathematics Advanced-Question 12-2023-Paper 1.png

The table shows the probability distribution of a discrete random variable. | x | 0 | 1 | 2 | 3 | 4 | |---|---|---|---|---|---| | P(X=x) | 0 | 0.3 | 0.5 | 0.1 | 0.1... show full transcript

Worked Solution & Example Answer:The table shows the probability distribution of a discrete random variable - HSC - SSCE Mathematics Advanced - Question 12 - 2023 - Paper 1

Step 1

Show that the expected value E(X) = 2.

96%

114 rated

Answer

To calculate the expected value E(X), we use the formula:

E(X)=extsum(ximesP(X=x))E(X) = ext{sum}(x imes P(X=x))

Calculating step-by-step:

  • For x=0x = 0: 0imesP(X=0)=0imes0=00 imes P(X=0) = 0 imes 0 = 0
  • For x=1x = 1: 1imesP(X=1)=1imes0.3=0.31 imes P(X=1) = 1 imes 0.3 = 0.3
  • For x=2x = 2: 2imesP(X=2)=2imes0.5=1.02 imes P(X=2) = 2 imes 0.5 = 1.0
  • For x=3x = 3: 3imesP(X=3)=3imes0.1=0.33 imes P(X=3) = 3 imes 0.1 = 0.3
  • For x=4x = 4: 4imesP(X=4)=4imes0.1=0.44 imes P(X=4) = 4 imes 0.1 = 0.4

Now, summing these values:

E(X)=0+0.3+1.0+0.3+0.4=2E(X) = 0 + 0.3 + 1.0 + 0.3 + 0.4 = 2

Thus, we have shown that the expected value E(X) = 2.

Step 2

Calculate the standard deviation, correct to one decimal place.

99%

104 rated

Answer

To calculate the standard deviation, we first find the variance Var(X) using the following formula:

Var(X)=E(X2)(E(X))2Var(X) = E(X^2) - (E(X))^2

We already found E(X)=2E(X) = 2. Now we need to compute E(X2)E(X^2):

  • For x=0x = 0: 02imesP(X=0)=0imes0=00^2 imes P(X=0) = 0 imes 0 = 0
  • For x=1x = 1: 12imesP(X=1)=1imes0.3=0.31^2 imes P(X=1) = 1 imes 0.3 = 0.3
  • For x=2x = 2: 22imesP(X=2)=4imes0.5=2.02^2 imes P(X=2) = 4 imes 0.5 = 2.0
  • For x=3x = 3: 32imesP(X=3)=9imes0.1=0.93^2 imes P(X=3) = 9 imes 0.1 = 0.9
  • For x=4x = 4: 42imesP(X=4)=16imes0.1=1.64^2 imes P(X=4) = 16 imes 0.1 = 1.6

Now, summing these values gives:

E(X2)=0+0.3+2.0+0.9+1.6=5.8E(X^2) = 0 + 0.3 + 2.0 + 0.9 + 1.6 = 5.8

Now substituting back to find the variance:

Var(X)=5.822=5.84=1.8Var(X) = 5.8 - 2^2 = 5.8 - 4 = 1.8

Finally, the standard deviation is the square root of the variance:

extStandarddeviation=extsqrt(1.8)1.3416 ext{Standard deviation} = ext{sqrt}(1.8) \approx 1.3416

Rounding to one decimal place gives:

extStandarddeviation=1.3 ext{Standard deviation} = 1.3

Join the SSCE students using SimpleStudy...

97% of Students

Report Improved Results

98% of Students

Recommend to friends

100,000+

Students Supported

1 Million+

Questions answered

;