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Which interval gives the range of the function $y = 5 + 2 ext{cos}(3x)$? A - HSC - SSCE Mathematics Advanced - Question 8 - 2020 - Paper 1

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Which-interval-gives-the-range-of-the-function-$y-=-5-+-2--ext{cos}(3x)$?-A-HSC-SSCE Mathematics Advanced-Question 8-2020-Paper 1.png

Which interval gives the range of the function $y = 5 + 2 ext{cos}(3x)$? A. [2, 8] B. [3, 7] C. [4, 6] D. [5, 9]

Worked Solution & Example Answer:Which interval gives the range of the function $y = 5 + 2 ext{cos}(3x)$? A - HSC - SSCE Mathematics Advanced - Question 8 - 2020 - Paper 1

Step 1

Identify the function

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Answer

The function given is y=5+2extcos(3x)y = 5 + 2 ext{cos}(3x). This is a cosine function which oscillates between -1 and 1.

Step 2

Determine the range of the cosine function

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Answer

The range of extcos(3x) ext{cos}(3x) is between -1 and 1. Therefore, the oscillation of the function y=5+2extcos(3x)y = 5 + 2 ext{cos}(3x) will be transformed by the coefficients.

Step 3

Calculate the maximum and minimum values

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Answer

The minimum value of the function occurs when extcos(3x)=1 ext{cos}(3x) = -1, which gives: ymin=5+2(1)=52=3y_{min} = 5 + 2(-1) = 5 - 2 = 3 The maximum value occurs when extcos(3x)=1 ext{cos}(3x) = 1, yielding: ymax=5+2(1)=5+2=7y_{max} = 5 + 2(1) = 5 + 2 = 7

Step 4

Establish the range

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Answer

Thus, the range of the function is from 3 to 7, or in interval notation: [3, 7].

Step 5

Select the correct answer

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Answer

The correct interval that gives the range of the function is option B: [3, 7].

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