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For real numbers a and b, where a ≠ 0 and b ≠ 0, we can find numbers α, β, γ, δ and R such that $a \, ext{cos}(x) + b \, ext{sin}(x)$ can be written in the following 4 forms: $$egin{align*} R \, ext{sin}(x + \alpha) \\ R \, ext{sin}(x - \beta) \\ R \, ext{cos}(x + \gamma) \\ R \, ext{cos}(x - \delta) \end{align*}$$ where $R > 0$ and $0 < \alpha, \beta, \gamma, \delta < 2\pi$ - HSC - SSCE Mathematics Extension 1 - Question 10 - 2024 - Paper 1

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Question 10

For-real-numbers-a-and-b,-where-a-≠-0-and-b-≠-0,-we-can-find-numbers-α,-β,-γ,-δ-and-R-such-that-$a-\,--ext{cos}(x)-+-b-\,--ext{sin}(x)$-can-be-written-in-the-following-4-forms:--$$egin{align*}-R-\,--ext{sin}(x-+-\alpha)-\\-R-\,--ext{sin}(x---\beta)-\\-R-\,--ext{cos}(x-+-\gamma)-\\-R-\,--ext{cos}(x---\delta)--\end{align*}$$--where-$R->-0$-and-$0-<-\alpha,-\beta,-\gamma,-\delta-<-2\pi$-HSC-SSCE Mathematics Extension 1-Question 10-2024-Paper 1.png

For real numbers a and b, where a ≠ 0 and b ≠ 0, we can find numbers α, β, γ, δ and R such that $a \, ext{cos}(x) + b \, ext{sin}(x)$ can be written in the followi... show full transcript

Worked Solution & Example Answer:For real numbers a and b, where a ≠ 0 and b ≠ 0, we can find numbers α, β, γ, δ and R such that $a \, ext{cos}(x) + b \, ext{sin}(x)$ can be written in the following 4 forms: $$egin{align*} R \, ext{sin}(x + \alpha) \\ R \, ext{sin}(x - \beta) \\ R \, ext{cos}(x + \gamma) \\ R \, ext{cos}(x - \delta) \end{align*}$$ where $R > 0$ and $0 < \alpha, \beta, \gamma, \delta < 2\pi$ - HSC - SSCE Mathematics Extension 1 - Question 10 - 2024 - Paper 1

Step 1

What is the value of α + β + γ + δ?

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Answer

To solve for the sum of angles, we recognize that the forms represent different phase shifts of the trigonometric functions. Each phase shift corresponds to a rotation.

Given that each form relates to sine and cosine of the same angle with shifts of α, β, γ, and δ being defined within the intervals, we know:

  • The total rotation (the full cycle) for each sine and cosine function concerning the unit circle is a complete 360 degrees, or 2π2\pi.
  • Since we can relate the forms back to one another through these phase shifts, the sum of all four angles must encapsulate one full cycle.

Thus, we conclude that: α+β+γ+δ=2π.\alpha + \beta + \gamma + \delta = 2\pi.

Therefore, the correct choice is C. 2π.

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