It is given that
$$
ext{cos} \left( \frac{23\pi}{12} \right) = \frac{\sqrt{6} + \sqrt{2}}{4} - HSC - SSCE Mathematics Extension 1 - Question 1 - 2022 - Paper 1
Question 1
It is given that
$$
ext{cos} \left( \frac{23\pi}{12} \right) = \frac{\sqrt{6} + \sqrt{2}}{4}.
$$
Which of the following is the value of
$$
\text{cos}^{-1} \left( ... show full transcript
Worked Solution & Example Answer:It is given that
$$
ext{cos} \left( \frac{23\pi}{12} \right) = \frac{\sqrt{6} + \sqrt{2}}{4} - HSC - SSCE Mathematics Extension 1 - Question 1 - 2022 - Paper 1
Step 1
Determine the angle for cosine
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Answer
To find the angle whose cosine value is given, we utilize the property of the inverse cosine function. Since we know that
cos(1223π)=46+2,
it follows that:
cos−1(46+2)=1223π.
Step 2
Evaluate possible options
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Answer
Upon comparing
\frac{23\pi}{12}, \frac{11\pi}{12}, \frac{\pi}{12}, \text{and} \frac{11\pi}{12}\n$$
we find that the value of
