Which of the following could be the graph of a solution to the differential equation
dy/dx = sin(y) + 1?
A - HSC - SSCE Mathematics Extension 1 - Question 10 - 2022 - Paper 1
Question 10
Which of the following could be the graph of a solution to the differential equation
dy/dx = sin(y) + 1?
A.
B.
C.
D.
Worked Solution & Example Answer:Which of the following could be the graph of a solution to the differential equation
dy/dx = sin(y) + 1?
A - HSC - SSCE Mathematics Extension 1 - Question 10 - 2022 - Paper 1
Step 1
Analyze the differential equation
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Answer
The given differential equation is of the form
dxdy=sin(y)+1. This indicates that the rate of change of y with respect to x is determined by the sine of y plus a constant 1. Notably, since sin(y) oscillates between -1 and 1, it follows that (\sin(y) + 1) oscillates between 0 and 2. Therefore, (\frac{dy}{dx} \geq 0) indicating that y is always non-decreasing.
Step 2
Consider the implications for the graph
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Answer
Given that (\frac{dy}{dx} \geq 0), the graph must either be increasing or remain constant. This rules out any options that display a decreasing trend as they would imply (\frac{dy}{dx} < 0). Furthermore, since the minimum value of (\frac{dy}{dx}) is 0 (when (\sin(y) = -1)), the graph will never have horizontal lines that collapse to a single point, ensuring that the function is always rising or leveling off, never declining.
Step 3
Evaluate each option
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Answer
Considering the options given:
Option A shows a decreasing function, thus invalid.
Option B shows a flat line at a certain y-value for large x, suggesting a meaningful upward trend, making it a valid solution.
Option C displays oscillations that extend down, which is not consistent with a non-decreasing function.
Option D shows a general upward trend with oscillations but may not meet the non-decreasing requirement overall.
Thus, Option B is the only plausible option as it represents a function that continues to rise or level out without decreasing.
Step 4
Final answer selection
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Answer
Based on the analysis, the correct graph that could represent a solution to the differential equation is B.