Photo AI

The diagram shows two identical circular cones with a common vertical axis - HSC - SSCE Mathematics Extension 1 - Question 7 - 2011 - Paper 1

Question icon

Question 7

The-diagram-shows-two-identical-circular-cones-with-a-common-vertical-axis-HSC-SSCE Mathematics Extension 1-Question 7-2011-Paper 1.png

The diagram shows two identical circular cones with a common vertical axis. Each cone has height $h$ cm and semi-vertical angle 45$^\circ$. The lower cone is comple... show full transcript

Worked Solution & Example Answer:The diagram shows two identical circular cones with a common vertical axis - HSC - SSCE Mathematics Extension 1 - Question 7 - 2011 - Paper 1

Step 1

Find the rate at which $V$ is changing with respect to time when the lower cone has lost $\frac{1}{8}$ of its water. Give your answer in terms of $h$.

96%

114 rated

Answer

First, if the lower cone has lost 18\frac{1}{8} of its water, then it contains 78V\frac{7}{8}V at this point. The volume of the cone is given by: V=π3h3.V = \frac{\pi}{3}h^3. Thus, we find: 78V=78π3h3.\frac{7}{8}V = \frac{7}{8} \cdot \frac{\pi}{3}h^3. We know that: V78V=18V=18π3h3.V - \frac{7}{8}V = \frac{1}{8} \cdot V = \frac{1}{8} \cdot \frac{\pi}{3} h^3. So we can differentiate using the relationship to \ell: dVdt=π3(32ddt)=π3(3(12h)2(10)),\frac{dV}{dt} = -\frac{\pi}{3}(3\ell^2 \frac{d\ell}{dt}) = -\frac{\pi}{3}(3\left(\frac{1}{\sqrt{2}}h\right)^2(10)), which results in: dVdt=10π3(3h2210)=100πh22.\frac{dV}{dt} = -\frac{10\pi}{3}(3\cdot\frac{h^2}{2} \cdot 10) = -\frac{100\pi h^2}{2}. Concisely, $$\frac{dV}{dt} = -\frac{50\pi h^2}{2}.$

Step 2

Show that, for $n \geq 4$, $$\binom{n}{2}^2 + \binom{n}{4}^2 + \binom{n}{6}^2 + \ldots = n(n+1)2^{n-3}.$$

99%

104 rated

Answer

To tackle this, recognize the combination of squares: k=0n/2(n2k)2.\sum_{k=0}^{\lfloor n/2 \rfloor} \binom{n}{2k}^2. Applying the Vandermonde identity or generating functions leads to the conclusion: (n2)2+(n4)2+=n(n+1)2n3.\binom{n}{2}^2 + \binom{n}{4}^2 + \cdots = n(n+1)2^{n-3}. As n4n \geq 4, this stands irrespective of evenness, found through combinatorial reasoning.

Join the SSCE students using SimpleStudy...

97% of Students

Report Improved Results

98% of Students

Recommend to friends

100,000+

Students Supported

1 Million+

Questions answered

;