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The angle between two unit vectors $\mathbf{a}$ and $\mathbf{b}$ is $\theta$ and $|\mathbf{a} + \mathbf{b}| < 1$ - HSC - SSCE Mathematics Extension 1 - Question 8 - 2022 - Paper 1

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The angle between two unit vectors $\mathbf{a}$ and $\mathbf{b}$ is $\theta$ and $|\mathbf{a} + \mathbf{b}| < 1$. Which of the following best describes the possible... show full transcript

Worked Solution & Example Answer:The angle between two unit vectors $\mathbf{a}$ and $\mathbf{b}$ is $\theta$ and $|\mathbf{a} + \mathbf{b}| < 1$ - HSC - SSCE Mathematics Extension 1 - Question 8 - 2022 - Paper 1

Step 1

Determine the Condition of the Vectors

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Answer

The condition a+b<1|\mathbf{a} + \mathbf{b}| < 1 implies that the vectors must form an angle of more than 00 degrees (or 00 radians) but less than 180180 degrees (or π\pi radians). This is because if the angle were 00, the vectors would point in the same direction, and their sum would be a+b=2|\mathbf{a}| + |\mathbf{b}| = 2, violating the condition. Conversely, if the angle were 180180 degrees, their sum would be a+b=0|\mathbf{a}| + |\mathbf{b}| = 0, which is also not allowed.

Step 2

Analyze the Angles and Select the Correct Range

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Answer

Considering the cosine of the angle between the two vectors, we know that: cos(θ)=ab1. \cos(\theta) = \mathbf{a} \cdot \mathbf{b} \leq 1. Since a+b<1|\mathbf{a} + \mathbf{b}| < 1, we establish that: θ>2π3\theta > \frac{2\pi}{3} to ensure the angle is obtuse. Thus, the only range that satisfies all conditions is: 2π3<θπ\frac{2\pi}{3} < \theta \leq \pi.

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