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Question 13
A particle is moving along the -x-axis in simple harmonic motion. The displacement of the particle is x metres and its velocity is v m s⁻¹. The parabola below shows ... show full transcript
Step 1
Answer
The particle is at rest when its velocity v is zero. From the equation v² = n²(a² - (x - c)²), setting v² to zero gives:
Solving for x results in:
Taking the square root of both sides gives:
Thus, the values of x where the particle is at rest are:
and .
Step 2
Step 3
Answer
The equation provided indicates the form of simple harmonic motion, where:
a is the amplitude of the motion,
c is the equilibrium position (the x-coordinate of the vertex of the parabola),
n relates to the angular frequency of the motion. Thus:
a corresponds to half the width of the parabola at the maximum height,
c is the x-value at the vertex of the parabola,
n is derived from the coefficient that relates to the speed at maximum displacement.
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