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Consider the polynomial $p(x) = ax^3 + bx^2 + cx - 6$ with $a$ and $b$ positive - HSC - SSCE Mathematics Extension 1 - Question 10 - 2016 - Paper 1

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Consider-the-polynomial-$p(x)-=-ax^3-+-bx^2-+-cx---6$-with-$a$-and-$b$-positive-HSC-SSCE Mathematics Extension 1-Question 10-2016-Paper 1.png

Consider the polynomial $p(x) = ax^3 + bx^2 + cx - 6$ with $a$ and $b$ positive. Which graph could represent $p(x)$? (A) (B) (C) (D)

Worked Solution & Example Answer:Consider the polynomial $p(x) = ax^3 + bx^2 + cx - 6$ with $a$ and $b$ positive - HSC - SSCE Mathematics Extension 1 - Question 10 - 2016 - Paper 1

Step 1

Determine the Behavior of the Polynomial

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Answer

Since a>0a > 0, the leading coefficient of p(x)p(x) is positive. This means that as x+x \to +\infty, p(x)+p(x) \to +\infty and as xx \to -\infty, p(x)p(x) \to -\infty. Therefore, we expect the polynomial to start low and rise as xx increases.

Step 2

Identify the Number of Turning Points

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Answer

A cubic polynomial can have up to 2 turning points. The graph should exhibit one or two local extrema, which means we expect it to change direction at least once.

Step 3

Analyze the Given Options

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Answer

Next, we evaluate the graphs:

  • Graph A: Starts low, rises toward the right, and has one turning point, fitting the expected behavior.
  • Graph B: Appears bounded on both ends and does not match the polynomial’s behavior.
  • Graph C: Starts low with a single turning point and ends at the same height, which is inconsistent for a cubic.
  • Graph D: Has a minimum and a maximum, but does not start low and rise high as it moves to the right.

Thus, only Graph A matches our analysis.

Step 4

Conclusion

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Answer

Based on the analysis of end behavior and turning points, the suitable graph to represent the polynomial p(x)p(x) is Graph A.

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