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Use mathematical induction to prove that $2^n + (-1)^{n+1}$ is divisible by 3 for all integers $n \geq 1$ - HSC - SSCE Mathematics Extension 1 - Question 13 - 2014 - Paper 1

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Use mathematical induction to prove that $2^n + (-1)^{n+1}$ is divisible by 3 for all integers $n \geq 1$. One end of a rope is attached to a truck and the other en... show full transcript

Worked Solution & Example Answer:Use mathematical induction to prove that $2^n + (-1)^{n+1}$ is divisible by 3 for all integers $n \geq 1$ - HSC - SSCE Mathematics Extension 1 - Question 13 - 2014 - Paper 1

Step 1

Use mathematical induction to prove that $2^n + (-1)^{n+1}$ is divisible by 3

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Answer

To prove this statement by mathematical induction, we first check the base case for n=1n = 1:

21+(1)1+1=2+1=32^1 + (-1)^{1+1} = 2 + 1 = 3 which is divisible by 3.

Inductive Step: Assume the statement is true for some integer k1k \geq 1, i.e.,

2k+(1)k+1=3m2^k + (-1)^{k+1} = 3m for some integer mm. We need to show that it holds for k+1k + 1:

2k+1+(1)(k+1)+1=22k+(1)k+2=22k12^{k+1} + (-1)^{(k+1)+1} = 2 \cdot 2^k + (-1)^{k+2} = 2 \cdot 2^k - 1 From the induction hypothesis, we substitute:

=2(3m(1)k+1)1=6m2(1)k+11= 2(3m - (-1)^{k+1}) - 1 = 6m - 2(-1)^{k+1} - 1 Calculate this expression:

=6m12(1)k+1=6m1+2(1)k+2= 6m - 1 - 2(-1)^{k+1} = 6m - 1 + 2(-1)^{k+2} Thus,

=3(2m1)= 3(2m - 1) This implies that 2(m1)+(1)k+22(m - 1) + (-1)^{k+2} is divisible by 3. Hence, the statement holds for n=k+1n = k + 1. By induction, the statement is true for all integers n1n \geq 1.

Step 2

Using Pythagoras' Theorem, or otherwise, show that $\frac{dL}{dx} = \cos \theta$

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Answer

By applying Pythagoras' theorem to the right triangle formed, where the vertical side is 40 m, the horizontal side is xx, and the hypotenuse is LL, we have:

L2=402+x2L^2 = 40^2 + x^2

Differentiating both sides with respect to xx, we apply implicit differentiation:

2LdLdx=2x2L \frac{dL}{dx} = 2x

From this, we isolate rac{dL}{dx}:

dLdx=xL\frac{dL}{dx} = \frac{x}{L}

From trigonometric relationships, we know:

cosθ=xL\cos \theta = \frac{x}{L}

Thus, we conclude that:

dLdx=cosθ\frac{dL}{dx} = \cos \theta

Step 3

Show that $\frac{dL}{dt} = 3 \cos \theta$

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Answer

Using the chain rule, we can express the rate of change of LL with respect to time tt as follows:

dLdt=dLdxdxdt\frac{dL}{dt} = \frac{dL}{dx} \cdot \frac{dx}{dt}

From the previous result, we know:

dLdx=cosθ\frac{dL}{dx} = \cos \theta

The truck moves at a constant speed of 3 m/s, so:

dxdt=3\frac{dx}{dt} = 3

Substituting these values, we find:

dLdt=cosθ3=3cosθ\frac{dL}{dt} = \cos \theta \cdot 3 = 3 \cos \theta

Thus, we have shown that:

dLdt=3cosθ\frac{dL}{dt} = 3 \cos \theta

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