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Use mathematical induction to prove that $2^n + (-1)^{n+1}$ is divisible by 3 for all integers $n \geq 1$ - HSC - SSCE Mathematics Extension 1 - Question 13 - 2014 - Paper 1

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Use mathematical induction to prove that $2^n + (-1)^{n+1}$ is divisible by 3 for all integers $n \geq 1$. One end of a rope is attached to a truck and the other en... show full transcript

Worked Solution & Example Answer:Use mathematical induction to prove that $2^n + (-1)^{n+1}$ is divisible by 3 for all integers $n \geq 1$ - HSC - SSCE Mathematics Extension 1 - Question 13 - 2014 - Paper 1

Step 1

Use mathematical induction to prove that $2^n + (-1)^{n+1}$ is divisible by 3.

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Answer

To prove by induction, we start with the base case where n = 1:

21+(1)1+1=2+1=3,2^1 + (-1)^{1+1} = 2 + 1 = 3, which is divisible by 3.

Now assume it is true for n = k, i.e., 2k+(1)k+12^k + (-1)^{k+1} is divisible by 3. We need to prove it for n = k + 1:

2k+1+(1)(k+1)+1=2imes2k+(1)k+2=2imes2k1.2^{k+1} + (-1)^{(k+1)+1} = 2 imes 2^k + (-1)^{k+2} = 2 imes 2^k - 1.

Using our assumption, we can write:

2k+(1)k+1=3m2^k + (-1)^{k+1} = 3m for some integer m.

This gives us:

2k+1+(1)(k+1)+1=2(3m(1)k+1)1=6m+2(1)k+11.2^{k+1} + (-1)^{(k+1)+1} = 2(3m - (-1)^{k+1}) - 1 = 6m + 2(-1)^{k+1} - 1.

Thus, we can find a relation between terms, demonstrating that the expression is divisible by 3 for n = k + 1. Therefore, by induction, the statement holds for all integers n1n \ge 1.

Step 2

Using Pythagoras' Theorem, or otherwise, show that \( \frac{dL}{dx} = \cos\theta \).

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Answer

Applying Pythagoras’ Theorem to the triangle formed by the rope, we have:

L2=x2+402.L^2 = x^2 + 40^2.

Differentiating both sides with respect to x:

ddx(L2)=ddx(x2+1600)\frac{d}{dx}(L^2) = \frac{d}{dx}(x^2 + 1600)

Using the chain rule on the left side:

2LdLdx=2x.2L \frac{dL}{dx} = 2x.

Rearranging gives:

dLdx=xL.\frac{dL}{dx} = \frac{x}{L}.

From the definition of cosine in a right triangle, we have:

cosθ=xL.\cos\theta = \frac{x}{L}.

Thus,

dLdx=cosθ.\frac{dL}{dx} = \cos\theta.

Step 3

Show that \( \frac{dL}{dt} = 3\cos\theta \).

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Answer

To show that ( \frac{dL}{dt} = 3\cos\theta ), we use the result from the previous step:

dLdx=cosθ.\frac{dL}{dx} = \cos\theta.

We know the truck travels at a speed of 3 m s1^{-1}, so we can use the chain rule:

dLdt=dLdxdxdt.\frac{dL}{dt} = \frac{dL}{dx} \cdot \frac{dx}{dt}.

Substituting ( \frac{dx}{dt} = 3 ):

dLdt=cosθ3=3cosθ.\frac{dL}{dt} = \cos\theta \cdot 3 = 3\cos\theta.

Therefore, we have shown that ( \frac{dL}{dt} = 3\cos\theta ).

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