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13 (15 marks) Use a SEPARATE writing booklet - HSC - SSCE Mathematics Extension 1 - Question 13 - 2014 - Paper 1

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13 (15 marks) Use a SEPARATE writing booklet. (a) Use mathematical induction to prove that $2^n + (-1)^{n+1}$ is divisible by 3 for all integers $n \geq 1$. (b) ... show full transcript

Worked Solution & Example Answer:13 (15 marks) Use a SEPARATE writing booklet - HSC - SSCE Mathematics Extension 1 - Question 13 - 2014 - Paper 1

Step 1

Use mathematical induction to prove that $2^n + (-1)^{n+1}$ is divisible by 3 for all integers $n \geq 1$

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Answer

We utilize the principle of mathematical induction.

  1. Base Case: For n=1n = 1, we have:

    21+(1)1+1=2+1=3,2^1 + (-1)^{1+1} = 2 + 1 = 3,

    which is divisible by 3.

  2. Inductive Step: Assume it holds for some integer kk, i.e., assume 2k+(1)k+12^k + (-1)^{k+1} is divisible by 3.

  3. We need to show that it also holds for k+1k + 1:

    2k+1+(1)(k+1)+1=2imes2k+(1)k+1.2^{k+1} + (-1)^{(k+1)+1} = 2 imes 2^k + (-1)^{k+1}.

    Substituting the inductive hypothesis in:

    =2(2k+(1)k+1)2(1)k+1.= 2(2^k + (-1)^{k+1}) - 2(-1)^{k+1}.

    Since 2k+(1)k+12^k + (-1)^{k+1} is divisible by 3, we can express it as:

    =3m2(1)k+1= 3m - 2(-1)^{k+1} for some integer mm.

    Depending on whether kk is even or odd, this reduces to showing 2(1)k+1-2(-1)^{k+1} is also divisible by 3. Hence, the statement is true for k+1k + 1, completing the induction.

Step 2

Using Pythagoras’ Theorem, or otherwise, show that $\frac{dL}{dx} = \cos \theta$

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Answer

In the given scenario, we apply Pythagoras’ Theorem:

  1. The relationship between LL, xx, and the height of the wheel is:

    L2=x2+402.L^2 = x^2 + 40^2.

  2. Taking the derivative of both sides with respect to xx:

    2LdLdx=2x.2L \frac{dL}{dx} = 2x.

    Thus, we find:

    dLdx=xL.\frac{dL}{dx} = \frac{x}{L}.

  3. From the triangle formed, we know that:

    cosθ=xL.\cos \theta = \frac{x}{L}. Therefore, we can write:

    dLdx=cosθ.\frac{dL}{dx} = \cos \theta.

Step 3

Show that $\frac{dL}{dt} = 3\cos \theta$

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Answer

From the previous step we have:

  1. We use the chain rule on LL with respect to time tt:

    dLdt=dLdxdxdt.\frac{dL}{dt} = \frac{dL}{dx} \cdot \frac{dx}{dt}.

  2. Substituting the expression we derived:

    dLdt=cosθdxdt.\frac{dL}{dt} = \cos \theta \cdot \frac{dx}{dt}.

  3. Given that the truck moves at 3 m/s:

    dxdt=3,\frac{dx}{dt} = 3, thus gives:

    dLdt=3cosθ.\frac{dL}{dt} = 3\cos \theta.

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