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What is the remainder when $2x^3 - 10x^2 + 6x + 2$ is divided by $x - 2$? (A) -66 (B) -10 (C) $-x^3 + 5x^2 - 3x - 1$ (D) $x^3 - 5x^2 + 3x + 1$ - HSC - SSCE Mathematics Extension 1 - Question 2 - 2016 - Paper 1

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What-is-the-remainder-when-$2x^3---10x^2-+-6x-+-2$-is-divided-by-$x---2$?-(A)--66-(B)--10-(C)-$-x^3-+-5x^2---3x---1$-(D)-$x^3---5x^2-+-3x-+-1$-HSC-SSCE Mathematics Extension 1-Question 2-2016-Paper 1.png

What is the remainder when $2x^3 - 10x^2 + 6x + 2$ is divided by $x - 2$? (A) -66 (B) -10 (C) $-x^3 + 5x^2 - 3x - 1$ (D) $x^3 - 5x^2 + 3x + 1$

Worked Solution & Example Answer:What is the remainder when $2x^3 - 10x^2 + 6x + 2$ is divided by $x - 2$? (A) -66 (B) -10 (C) $-x^3 + 5x^2 - 3x - 1$ (D) $x^3 - 5x^2 + 3x + 1$ - HSC - SSCE Mathematics Extension 1 - Question 2 - 2016 - Paper 1

Step 1

Step 1: Identify the Function

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Answer

We have the polynomial function given by f(x)=2x310x2+6x+2f(x) = 2x^3 - 10x^2 + 6x + 2. We need to find the remainder when this polynomial is divided by x2x - 2.

Step 2

Step 2: Apply the Remainder Theorem

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Answer

According to the Remainder Theorem, the remainder of the division of a polynomial f(x)f(x) by xcx - c is equal to f(c)f(c). Here, we will substitute c=2c = 2 into the polynomial.

Calculating: f(2)=2(2)310(2)2+6(2)+2f(2) = 2(2)^3 - 10(2)^2 + 6(2) + 2

This evaluates as follows: =2(8)10(4)+12+2= 2(8) - 10(4) + 12 + 2 =1640+12+2= 16 - 40 + 12 + 2 =1640+14= 16 - 40 + 14 =24+14= -24 + 14 =10= -10

Step 3

Step 3: Conclusion

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Answer

Thus, the remainder when 2x310x2+6x+22x^3 - 10x^2 + 6x + 2 is divided by x2x - 2 is -10. Hence, the correct answer is (B) -10.

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