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The diagram shows quadrilateral ABCD and the bisectors of the angles at A, B, C and D - HSC - SSCE Mathematics Extension 1 - Question 14 - 2018 - Paper 1

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The diagram shows quadrilateral ABCD and the bisectors of the angles at A, B, C and D. The bisectors at A and B intersect at the point P. The bisectors at A and D me... show full transcript

Worked Solution & Example Answer:The diagram shows quadrilateral ABCD and the bisectors of the angles at A, B, C and D - HSC - SSCE Mathematics Extension 1 - Question 14 - 2018 - Paper 1

Step 1

Show that PQRS is a cyclic quadrilateral

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Answer

To demonstrate that quadrilateral PQRS is cyclic, we must show that the opposite angles are supplementary.

Step 1: Angle Relationships

  • Let
    • rac{1}{2} A = a,
    • rac{1}{2} B = b,
    • rac{1}{2} C = c,
    • rac{1}{2} D = d.

Step 2: Sum of Opposite Angles

  • By the properties of angle bisectors and angles in a cyclic quadrilateral, we find:

    • Angle PQR + Angle PSR = 180°
    • b+d=180°b + d = 180° (from angles at B and D)
  • Similarly,

    • Angle QRS + Angle RSP = 180°
    • a+c=180°a + c = 180° (from angles at A and C)

Thus, since opposite angles sum to 180°, we can conclude that PQRS is a cyclic quadrilateral.

Step 2

By considering the expansions of (1 + (1 + x)^y) and (2 + y^x), show that

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Answer

We start by expanding both expressions:

Expansion of (1 + (1 + x)^y)

  • Using the binomial theorem, the expansion is: ext{Coefficient of } x^{r} = {y race r}

Expansion of (2 + y^x)

  • Similarly, this can be expanded: ext{Coefficient of } x^{r} = {r race r}

Equating coefficients gives: {n race r} (r + 1) = {n race r}

Conclusion

This demonstrates the required relationship.

Step 3

There are 23 people who have applied to be selected for a committee of 4 people. The selection process starts with Selector A choosing a group of at least 4 people from the 23 people who applied. Selector B then chooses the 4 people to be on the committee from the group Selector A has chosen. In how many ways could this selection process be carried out?

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Answer

Step 1: Choose at least 4 people

  • Selector A can choose between 4 to 23 people: extTotalways=k=423(23k) ext{Total ways} = \sum_{k=4}^{23} {23 \choose k}

Step 2: Choose 4 from the chosen group

After selector A's choice of kk people, Selector B has: (k4){k \choose 4} ways to choose the committee .

Final Count

To find the total number of ways: extTotal=k=423(23k)(k4) ext{Total} = \sum_{k=4}^{23} {23 \choose k} {k \choose 4}

Evaluating the Sum

This calculation can be performed using combinatorial identities to arrive at the final total.

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