Maria starts at the origin and walks along all of the vector $2 extbf{i} + 3 extbf{j}$, then walks along all of the vector $3 extbf{i} - 2 extbf{j}$ and finally along all of the vector $4 extbf{i} - 3 extbf{j}$ - HSC - SSCE Mathematics Extension 1 - Question 4 - 2020 - Paper 1

From the point (2,3), Maria walks the vector $3 extbf{i} - 2 extbf{j}$, moving to the point (2+3, 3-2) = (5,1).

From the point (5,1), she then walks the vector $4 extbf{i} - 3 extbf{j}$, reaching the point (5+4, 1-3) = (9,-2).

Using the distance formula, distance $d$ from the origin to the point (9,-2) is given by: $d = ext{sqr}(9^2 + (-2)^2) = ext{sqr}(81 + 4) = ext{sqr}(85) = ext{√85}$ Thus, the distance from the origin is $= ext{√85}$.