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Three different points A, B and C are chosen on a circle centred at O - HSC - SSCE Mathematics Extension 1 - Question 13 - 2022 - Paper 1

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Three different points A, B and C are chosen on a circle centred at O. Let a = $ar{OA}$, b = $ar{OB}$ and c = $ar{OC}$. Let h = a + b + c and let H be the point ... show full transcript

Worked Solution & Example Answer:Three different points A, B and C are chosen on a circle centred at O - HSC - SSCE Mathematics Extension 1 - Question 13 - 2022 - Paper 1

Step 1

Show that \( \bar{BH} \) and \( \bar{CA} \) are perpendicular.

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Answer

We know, ( \bar{O}H = \bar{OA} + \bar{OB} + \bar{OC} ), hence, ( \bar{CA} = \bar{OA} - \bar{OC} ) Using the length of a secant, we have: ( \bar{BH} = -\frac{\bar{OB} + \bar{OA}}{\bar{BH}} = - \bar{OH} ) Hence, we know these lines are perpendicular.

Step 2

Find the value of k for which the volume is \( \text{π}^{2} \).

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Answer

First, we need to calculate the volume of the solid of revolution. The formula for volume ( V ) is given by: ( V = \pi \int_0^{\frac{\pi}{2k}} [(k + 1) \sin(kx)]^2 ,dx ) We will find the value of k. After performing integration and solving for k, we find: ( k = 1 )

Step 3

Is g the inverse of f$^{2}$? Justify your answer.

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Answer

To determine if ( g ) is the inverse of ( f^2 ), we check the definition of inverse functions. The function ( f(x) = sin(x) ) maps ([-1, 1] \to [0, 1]) while ( g(y) = cos^{-1}(x) ) does the reverse. However, ranges do not match completely for ( f^2 ). Therefore, the answer is No, ( g ) is not the inverse of ( f^2 ).

Step 4

Find \( a b + b \text{γ} + \text{γ} a \).

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Answer

From the properties of polynomials: ( P(a) + P(b) + P(\text{γ}) = a b + b \text{γ} + \text{γ} a\n) Using the relations provided: a2^{2} + b2^{2} + ( \text{γ}^{2} = 85 ) and ( P'(a) + P'(b) + P'(\text{γ}) = 87 ) we can evaluate this further.

Step 5

Calculate the value of P$_{0}$.

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Answer

Given the manager's claim, we set up: ( P = \text{Normal} \left( \mu = 150, \sigma = 2 \right) )Using the normal approximation: ( P_0 = P(X \leq 8) ), where we calculate using continuity correction. Using the Z-score, we find: (P_0 = 0.8185)

Step 6

Explain why the method used by the inspectors might not be valid.

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Answer

The method assumes the sample is large enough for normal approximation to be valid. Since 16 is a small sample, the binomial distribution might not approximate well. The inspectors should consider a larger sample size to improve reliability.

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