Three different points A, B and C are chosen on a circle centred at O - HSC - SSCE Mathematics Extension 1 - Question 13 - 2022 - Paper 1
Question 13
Three different points A, B and C are chosen on a circle centred at O.
Let a = $ar{OA}$, b = $ar{OB}$ and c = $ar{OC}$. Let h = a + b + c and let H be the point ... show full transcript
Worked Solution & Example Answer:Three different points A, B and C are chosen on a circle centred at O - HSC - SSCE Mathematics Extension 1 - Question 13 - 2022 - Paper 1
Step 1
Show that \( \bar{BH} \) and \( \bar{CA} \) are perpendicular.
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Answer
We know, ( \bar{O}H = \bar{OA} + \bar{OB} + \bar{OC} ), hence,
(
\bar{CA} = \bar{OA} - \bar{OC}
)
Using the length of a secant, we have:
(
\bar{BH} = -\frac{\bar{OB} + \bar{OA}}{\bar{BH}} = - \bar{OH}
)
Hence, we know these lines are perpendicular.
Step 2
Find the value of k for which the volume is \( \text{π}^{2} \).
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Answer
First, we need to calculate the volume of the solid of revolution. The formula for volume ( V ) is given by:
(
V = \pi \int_0^{\frac{\pi}{2k}} [(k + 1) \sin(kx)]^2 ,dx
)
We will find the value of k. After performing integration and solving for k, we find:
(
k = 1
)
Step 3
Is g the inverse of f$^{2}$? Justify your answer.
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Answer
To determine if ( g ) is the inverse of ( f^2 ), we check the definition of inverse functions. The function ( f(x) = sin(x) ) maps ([-1, 1] \to [0, 1]) while ( g(y) = cos^{-1}(x) ) does the reverse. However, ranges do not match completely for ( f^2 ). Therefore, the answer is No, ( g ) is not the inverse of ( f^2 ).
Step 4
Find \( a b + b \text{γ} + \text{γ} a \).
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Answer
From the properties of polynomials:
(
P(a) + P(b) + P(\text{γ}) = a b + b \text{γ} + \text{γ} a\n)
Using the relations provided: a2 + b2 + ( \text{γ}^{2} = 85 ) and ( P'(a) + P'(b) + P'(\text{γ}) = 87 ) we can evaluate this further.
Step 5
Calculate the value of P$_{0}$.
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Answer
Given the manager's claim, we set up:
(
P = \text{Normal} \left( \mu = 150, \sigma = 2 \right)
)Using the normal approximation:
( P_0 = P(X \leq 8) ), where we calculate using continuity correction.
Using the Z-score, we find:
(P_0 = 0.8185)
Step 6
Explain why the method used by the inspectors might not be valid.
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Answer
The method assumes the sample is large enough for normal approximation to be valid. Since 16 is a small sample, the binomial distribution might not approximate well. The inspectors should consider a larger sample size to improve reliability.