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12 marks) Use the Question 12 Writing Booklet - HSC - SSCE Mathematics Extension 1 - Question 12 - 2022 - Paper 1

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12 marks) Use the Question 12 Writing Booklet. a) A direction field is to be drawn for the differential equation dy/dx = -x - 2y / x^2 + y^2 On the diagram on pag... show full transcript

Worked Solution & Example Answer:12 marks) Use the Question 12 Writing Booklet - HSC - SSCE Mathematics Extension 1 - Question 12 - 2022 - Paper 1

Step 1

A direction field is to be drawn for the differential equation

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Answer

To draw a direction field for the equation dydx=x2yx2+y2\frac{dy}{dx} = -\frac{x - 2y}{x^2 + y^2}, we need to compute the slopes at specific points, for example, P, Q, and R. Insert values of x and y into the right-hand side of the equation to find the corresponding slopes. Then, on the direction field diagram, draw line segments indicating these slopes at the specified points.

Step 2

Will any team be penalised? Justify your answer.

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Number of players above limit = 41.

Since there are 13 teams, the maximum number of players allowed over the limit for each team is 3. Therefore, the maximum number of players above the limit without penalty is: 3×13=39.3 \times 13 = 39. Since there are 41 players above the age limit, at least one team will be penalised as they exceed the allowed number of 39.

Step 3

Find the equation of the tangent to the curve y = x arctan(x) at the point with coordinates (1, π/4).

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First, we need to find the derivative of the curve: y=ddx(xarctan(x))y' = \frac{d}{dx}(x \cdot \arctan(x)) Using the product rule, we have: y=arctan(x)+x11+x2.y' = \arctan(x) + x \cdot \frac{1}{1 + x^2}.

Next, we evaluate the derivative at x = 1: y(1)=arctan(1)+111+12=π4+12=π4+0.5.y'(1) = \arctan(1) + 1 \cdot \frac{1}{1 + 1^2} = \frac{\pi}{4} + \frac{1}{2} = \frac{\pi}{4} + 0.5.

The slope of the tangent at the point (1, \frac{\pi}{4}) is therefore: m=π4+0.5.m = \frac{\pi}{4} + 0.5.

Using the point-slope form, we plug in our point and slope: yπ4=m(x1).y - \frac{\pi}{4} = m(x - 1).

Simplifying this gives our final tangent line equation in the form y = mx + c.

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