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Three unit vectors a, b and c in 3 dimensions, are to be chosen so that a ⊥ b, b ⊥ c and the angle θ between a and b + c is as small as possible - HSC - SSCE Mathematics Extension 2 - Question 10 - 2024 - Paper 1

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Three unit vectors a, b and c in 3 dimensions, are to be chosen so that a ⊥ b, b ⊥ c and the angle θ between a and b + c is as small as possible. What is the value ... show full transcript

Worked Solution & Example Answer:Three unit vectors a, b and c in 3 dimensions, are to be chosen so that a ⊥ b, b ⊥ c and the angle θ between a and b + c is as small as possible - HSC - SSCE Mathematics Extension 2 - Question 10 - 2024 - Paper 1

Step 1

Given the Unit Vectors and Conditions

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Answer

The problem states that we have three unit vectors a, b, and c such that:

  • a is perpendicular to b ( ( a \perp b ) )
  • b is perpendicular to c ( ( b \perp c ) ) This implies that the vectors are mutually orthogonal and lie in three-dimensional space.

Step 2

Calculate the Angles and Relationships

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Answer

To minimize the angle θ between vector a and the sum of vectors b and c, we can use the geometric property of unit vectors in three dimensions. Since a, b, and c are orthogonal, we find that:

  1. The vector sum b + c is still a unit vector. We can express this sum as:

    b+c=b2+c2=1+1=2b + c = \sqrt{b^2 + c^2} = \sqrt{1 + 1} = \sqrt{2}

  2. The angle θ can then be calculated using the dot product. Since all vectors are unit vectors and orthogonal:

    cos(θ) = \frac{a ullet (b + c)}{|a| |b + c|} = \frac{0}{|b + c|} = 0

Step 3

Providing the Answer Cos θ

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Answer

Given that the angle between a and (b + c) is minimized, the cosine of this angle is:

cos(θ)=0cos(θ) = 0

Therefore, the answer is:

Option A: 0.

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