It is known that a particular complex number $z$ is NOT a real number - HSC - SSCE Mathematics Extension 2 - Question 6 - 2022 - Paper 1
Question 6
It is known that a particular complex number $z$ is NOT a real number.
Which of the following could be true for this number $z$?
A. $\bar{z} = iz$
B. $\bar{z} = |... show full transcript
Worked Solution & Example Answer:It is known that a particular complex number $z$ is NOT a real number - HSC - SSCE Mathematics Extension 2 - Question 6 - 2022 - Paper 1
Step 1
$\bar{z} = iz$
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Answer
This equation states that the conjugate of the complex number z is equal to iz. For a complex number z=x+iy, the conjugate is zˉ=x−iy. Setting x−iy=i(x+iy) leads to a contradiction unless y=0, meaning z wouldn't be a non-real number. Therefore, this cannot be true.
Step 2
$\bar{z} = |z|$
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Answer
This statement asserts that the conjugate of z equals the modulus of z. Since ∣z∣ is always a non-negative real number and the conjugate indicates that the imaginary component must be zero for equality, this option cannot be true for a non-real z.
Step 3
$\text{Re}(iz) = \text{Im}(z)$
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Answer
For z=x+iy, iz=i(x+iy)=−y+ix. Thus, Re(iz)=−y and Im(z)=y. This leads to the equation −y=y, which can hold true when y=0. However, since z is non-real, this can be true under certain conditions, making it a potential candidate.
Step 4
$\text{Arg}(z^3) = \text{Arg}(z)$
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The argument of a complex number relates to its angle in the complex plane. For a non-real number z, Arg(z3)=3⋅Arg(z). This implies that Arg(z) can equal Arg(z3) only if n⋅Arg(z) is a multiple of 2π. Hence, this could potentially be true under certain circumstances.