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It is known that a particular complex number $z$ is NOT a real number - HSC - SSCE Mathematics Extension 2 - Question 6 - 2022 - Paper 1

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It is known that a particular complex number $z$ is NOT a real number. Which of the following could be true for this number $z$? A. $\bar{z} = iz$ B. $\bar{z} = |... show full transcript

Worked Solution & Example Answer:It is known that a particular complex number $z$ is NOT a real number - HSC - SSCE Mathematics Extension 2 - Question 6 - 2022 - Paper 1

Step 1

$\bar{z} = iz$

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Answer

This equation states that the conjugate of the complex number zz is equal to iziz. For a complex number z=x+iyz = x + iy, the conjugate is zˉ=xiy\bar{z} = x - iy. Setting xiy=i(x+iy)x - iy = i(x + iy) leads to a contradiction unless y=0y = 0, meaning zz wouldn't be a non-real number. Therefore, this cannot be true.

Step 2

$\bar{z} = |z|$

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Answer

This statement asserts that the conjugate of zz equals the modulus of zz. Since z|z| is always a non-negative real number and the conjugate indicates that the imaginary component must be zero for equality, this option cannot be true for a non-real zz.

Step 3

$\text{Re}(iz) = \text{Im}(z)$

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Answer

For z=x+iyz = x + iy, iz=i(x+iy)=y+ixiz = i(x + iy) = -y + ix. Thus, Re(iz)=y\text{Re}(iz) = -y and Im(z)=y\text{Im}(z) = y. This leads to the equation y=y-y = y, which can hold true when y=0y = 0. However, since zz is non-real, this can be true under certain conditions, making it a potential candidate.

Step 4

$\text{Arg}(z^3) = \text{Arg}(z)$

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Answer

The argument of a complex number relates to its angle in the complex plane. For a non-real number zz, Arg(z3)=3Arg(z)\text{Arg}(z^3) = 3 \cdot \text{Arg}(z). This implies that Arg(z)\text{Arg}(z) can equal Arg(z3)\text{Arg}(z^3) only if nArg(z)n \cdot \text{Arg}(z) is a multiple of 2π2\pi. Hence, this could potentially be true under certain circumstances.

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