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The complex number z is such that |z| = 2 and arg(z) = \frac{\pi}{4} - HSC - SSCE Mathematics Extension 2 - Question 12 - 2015 - Paper 1

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The complex number z is such that |z| = 2 and arg(z) = \frac{\pi}{4}. Plot each of the following complex numbers on the same half-page Argand diagram. (i) z (ii... show full transcript

Worked Solution & Example Answer:The complex number z is such that |z| = 2 and arg(z) = \frac{\pi}{4} - HSC - SSCE Mathematics Extension 2 - Question 12 - 2015 - Paper 1

Step 1

Plot each of the following complex numbers on the same half-page Argand diagram: (i) z

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Answer

To plot the complex number z, we start with the polar coordinates derived from the given conditions. Given that |z| = 2 and arg(z) = \frac{\pi}{4}, we first convert to Cartesian form:

z=2(cos(π4)+isin(π4))=2(22+i22)=2+i2z = 2 \left( \cos \left( \frac{\pi}{4} \right) + i \sin \left( \frac{\pi}{4} \right) \right) = 2 \left( \frac{\sqrt{2}}{2} + i \frac{\sqrt{2}}{2} \right) = \sqrt{2} + i\sqrt{2}

On the Argand diagram, we plot the point ((\sqrt{2}, \sqrt{2})), which lies in the first quadrant.

Step 2

Plot each of the following complex numbers on the same half-page Argand diagram: (ii) u = z^2

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To find u, we calculate:

u=z2=(2+i2)2=2+2i22=2i2u = z^2 = (\sqrt{2} + i \sqrt{2})^2 = 2 + 2i\sqrt{2} - 2 = 2i\sqrt{2}

Now in Cartesian form, we plot the point (0, 2\sqrt{2}) on the Argand diagram, which lies on the positive imaginary axis.

Step 3

Plot each of the following complex numbers on the same half-page Argand diagram: (iii) v = z^2 - \overline{z}

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First, we need to compute the conjugate of z:

z=2i2\overline{z} = \sqrt{2} - i\sqrt{2}

Now, substituting for v:

v=z2z=2i2(2i2)=(0+2i2)(2i2)=(2+i2)v = z^2 - \overline{z} = 2i\sqrt{2} - (\sqrt{2} - i\sqrt{2}) = (0 + 2i\sqrt{2}) - (\sqrt{2} - i\sqrt{2}) = (\sqrt{2} + i\sqrt{2})

Plot the resultant vector on the Argand diagram.

Step 4

By evaluating a and b, find all the roots of P(x): (i)

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Answer

To find the roots of polynomial P(x), we need to evaluate the polynomial at various x-values. By applying the Rational Root Theorem and synthetic division, we can determine that:

The roots are x = 1, 2, 3 + i, 3 - i. Here, a = 3 and b = 1.

Step 5

Hence, or otherwise, find one quadratic polynomial with real coefficients that is a factor of P(x): (ii)

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Answer

The complex roots (3 + i) and (3 - i) suggest a quadratic factor:

Q(x)=(x(3+i))(x(3i))=(x3i)(x3+i)=(x3)2+1=x26x+10Q(x) = (x - (3 + i))(x - (3 - i)) = (x - 3 - i)(x - 3 + i) = (x - 3)^2 + 1 = x^2 - 6x + 10

This quadratic polynomial has real coefficients and is a factor of P(x).

Step 6

By writing \frac{(x - 2)(x - 5)}{x - 1} in the form mx + b + \frac{a}{x - 1}: (c)(i)

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Answer

To express (\frac{(x - 2)(x - 5)}{x - 1}) in the desired form: Perform polynomial long division:

  1. Divide (x - 2)(x - 5) by (x - 1):

Using synthetic division, we arrive at: m=2,b=7,a=3,    (x2)(x5)x1=2x7+3x1m = 2, b = -7, a = -3, \implies \frac{(x - 2)(x - 5)}{x - 1} = 2x - 7 + \frac{-3}{x - 1}

Step 7

Hence sketch the graph y = \frac{(x - 2)(x - 5)}{x - 1}: (c)(ii)

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Answer

The expression simplifies, showing vertical asymptotes at x = 1 and x-intercepts at x = 2 and x = 5. Additionally, the oblique asymptote derived from previous calculations is y = 2x - 7. Therefore, sketching the graph involves indicating intercepts and asymptotes in the Cartesian plane.

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