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The diagram shows the graph $y=e^{x}$ for $0 \leq x \leq 4$ - HSC - SSCE Mathematics Extension 2 - Question 5 - 2018 - Paper 1

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The diagram shows the graph $y=e^{x}$ for $0 \leq x \leq 4$. The region bounded by $y=-1$, $y=e^{x}$, $x=0$ and $x=4$ is rotated about the line $y=-1$ to form a soli... show full transcript

Worked Solution & Example Answer:The diagram shows the graph $y=e^{x}$ for $0 \leq x \leq 4$ - HSC - SSCE Mathematics Extension 2 - Question 5 - 2018 - Paper 1

Step 1

Identify the boundaries of the solid

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Answer

The solid is formed by rotating the area between the curve y=exy=e^{x}, the line y=1y=-1, and the vertical lines x=0x=0 and x=4x=4. This defines a solid with a radius that depends on the distance from the line y=1y=-1 to the curve.

Step 2

Determine the radius of the solid

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Answer

The radius of a cross-section at point xx is given by the distance from y=1y=-1 to y=exy=e^{x}. Therefore, the radius can be expressed as:

R(x)=ex(1)=ex+1R(x) = e^{x} - (-1) = e^{x} + 1

Step 3

Set up the volume integral using the disk method

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Answer

The volume VV of the solid obtained by rotating the area around the line y=1y=-1 can be calculated using the disk method, leading to the integral:

V=π04(R(x))2dx=π04(ex+1)2dxV = \pi \int_{0}^{4} (R(x))^{2} dx = \pi \int_{0}^{4} (e^{x}+1)^{2} dx

Step 4

Conclusion

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Answer

Hence, the correct integral representing the volume of the solid formed is:

A. π04(ex+1)2dx\pi \int_{0}^{4} (e^{x}+1)^{2} dx

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