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12. (a) Using the substitution $t = \tan \frac{x}{2}$, evaluate \( \int_{0}^{\frac{\pi}{2}} \frac{1}{4 + 5 \cos x} \, dx \).\n\n(b) The equation $\log_{y} \left(1000 - y \right) = \frac{x}{50} - \log_{3} y$ implicitly defines $y$ as a function of $x$.\nShow that $y$ satisfies the differential equation $\frac{dy}{dx} = \frac{y}{50} \left(1 - \frac{y}{1000} \right)$.\n\n(c) The diagram shows the region bounded by the graph $y = e^{x}$, the $x$-axis and the lines $x=1$ and $x=3$ - HSC - SSCE Mathematics Extension 2 - Question 12 - 2013 - Paper 1

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Question 12

12.-(a)-Using-the-substitution-$t-=-\tan-\frac{x}{2}$,-evaluate-\(-\int_{0}^{\frac{\pi}{2}}-\frac{1}{4-+-5-\cos-x}-\,-dx-\).\n\n(b)-The-equation-$\log_{y}-\left(1000---y-\right)-=-\frac{x}{50}---\log_{3}-y$-implicitly-defines-$y$-as-a-function-of-$x$.\nShow-that-$y$-satisfies-the-differential-equation-$\frac{dy}{dx}-=-\frac{y}{50}-\left(1---\frac{y}{1000}-\right)$.\n\n(c)-The-diagram-shows-the-region-bounded-by-the-graph-$y-=-e^{x}$,-the-$x$-axis-and-the-lines-$x=1$-and-$x=3$-HSC-SSCE Mathematics Extension 2-Question 12-2013-Paper 1.png

12. (a) Using the substitution $t = \tan \frac{x}{2}$, evaluate \( \int_{0}^{\frac{\pi}{2}} \frac{1}{4 + 5 \cos x} \, dx \).\n\n(b) The equation $\log_{y} \left(1000... show full transcript

Worked Solution & Example Answer:12. (a) Using the substitution $t = \tan \frac{x}{2}$, evaluate \( \int_{0}^{\frac{\pi}{2}} \frac{1}{4 + 5 \cos x} \, dx \).\n\n(b) The equation $\log_{y} \left(1000 - y \right) = \frac{x}{50} - \log_{3} y$ implicitly defines $y$ as a function of $x$.\nShow that $y$ satisfies the differential equation $\frac{dy}{dx} = \frac{y}{50} \left(1 - \frac{y}{1000} \right)$.\n\n(c) The diagram shows the region bounded by the graph $y = e^{x}$, the $x$-axis and the lines $x=1$ and $x=3$ - HSC - SSCE Mathematics Extension 2 - Question 12 - 2013 - Paper 1

Step 1

Using the substitution $t = \tan \frac{x}{2}$, evaluate \( \int_{0}^{\frac{\pi}{2}} \frac{1}{4 + 5 \cos x} \, dx \)

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Answer

To evaluate ( \int_{0}^{\frac{\pi}{2}} \frac{1}{4 + 5 \cos x} , dx ) using the substitution t=tanx2t = \tan \frac{x}{2}, we first find the relationship between dxdx and dtdt:

dx=2dt1+t2dx = \frac{2 \, dt}{1 + t^{2}}

Next, we convert the limits of integration. When x=0x = 0, t=0t = 0; when x=π2x = \frac{\pi}{2}, t=1t = 1. The cosine function becomes:

cosx=1t21+t2\cos x = \frac{1 - t^{2}}{1 + t^{2}}

Substituting into the integral gives:

0124+5(1t21+t2)2dt1+t2\int_{0}^{1} \frac{2}{4 + 5 \left(\frac{1 - t^{2}}{1 + t^{2}}\right)} \cdot \frac{2 \, dt}{1 + t^{2}}

Now simplify and integrate to find the result.

Step 2

Show that $y$ satisfies the differential equation $\frac{dy}{dx} = \frac{y}{50} \left(1 - \frac{y}{1000} \right)$

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Answer

To show this, start with the given equation:

logy(1000y)=x50log3y\log_{y} (1000 - y) = \frac{x}{50} - \log_{3} y

Differentiate both sides with respect to xx, applying the implicit differentiation:

Using the change of base formula for log\log, we derive:

ddxlogy(1000y)=1(1000y)(dydx)1yln(10)\frac{d}{dx} \log_{y} (1000 - y) = \frac{1}{(1000 - y)} \cdot \left(-\frac{dy}{dx} \right) \cdot \frac{1}{y \ln(10)}

Then we can rearrange to show that:

dydx=y(1000y)50ln(3)\frac{dy}{dx} = \frac{y \cdot (1000 - y)}{50 \cdot \ln(3)}

Simplifying this gives the required differential equation.

Step 3

Find the volume of the solid.

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Answer

To find the volume of the solid formed by rotating the area between y=exy = e^{x}, the xx-axis, and the lines x=1x=1 and x=3x=3 about the line x=4x=4, use the method of cylindrical shells:

The volume is given by:

V=2π13(4x)exdxV = 2 \pi \int_{1}^{3} (4 - x) e^{x} \, dx

Evaluate this integral:

  1. Set up the substitution for the integral.
  2. Integrate to find the volume and simplify.

Step 4

Show that the equation of the tangent at $P$ is $x + py^{2} = 2cp$

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Answer

To show that the tangent line at point PP is given by the equation, first determine the slope at point PP on the hyperbola:

dydx=qp\frac{dy}{dx} = -\frac{q}{p}

Use point-slope form for the equation of the tangent line through point PP:

yyP=m(xxP)y - y_{P} = m (x - x_{P})

After substituting mm and rearranging, the desired equation can be obtained.

Step 5

Show that $A$, $B$ and $O$ are on a circle with centre $P$

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Answer

To show that points AA, BB, and OO are co-circular with center PP, calculate the distances from PP to each of the points. The geometric properties and the cyclic nature of the points will establish the result using the circumcircle theorem.

Step 6

Prove that $BC$ is parallel to $PQ$

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Answer

To prove that line segment BCBC is parallel to PQPQ, check the slopes of the lines. Using coordinate geometry or derivative calculations, demonstrate that the slopes are equal, confirming the parallel nature.

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