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It is given that $$|z - 1 + i| = 2.$$ What is the maximum possible value of $$|z|?$$ - HSC - SSCE Mathematics Extension 2 - Question 7 - 2024 - Paper 1

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It-is-given-that---$$|z---1-+-i|-=-2.$$---What-is-the-maximum-possible-value-of---$$|z|?$$-HSC-SSCE Mathematics Extension 2-Question 7-2024-Paper 1.png

It is given that $$|z - 1 + i| = 2.$$ What is the maximum possible value of $$|z|?$$

Worked Solution & Example Answer:It is given that $$|z - 1 + i| = 2.$$ What is the maximum possible value of $$|z|?$$ - HSC - SSCE Mathematics Extension 2 - Question 7 - 2024 - Paper 1

Step 1

Find the expression of $|z|$

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Answer

Let z=x+yiz = x + yi, where xx and yy are real numbers. Then, we can rewrite the equation as:

z(1i)=2|z - (1 - i)| = 2

This implies that the distance from the point (1,1)(1, -1) in the complex plane to the point (x,y)(x, y) is equal to 22.

Step 2

Geometric Interpretation

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Answer

This describes a circle centered at the point (1,1)(1, -1) with a radius of 22. The equation can be expressed as:

(x1)2+(y+1)2=4.(x - 1)^2 + (y + 1)^2 = 4.

Step 3

Maximize $|z| = |x + yi|$

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Answer

To find the maximum value of z|z|, we need to maximize:

z=extdistancefromtheoriginto(x,y),|z| = ext{distance from the origin to } (x, y),

which is given by:

z=extsqrt(x2+y2).|z| = ext{sqrt}(x^2 + y^2).

The maximum distance occurs when the circle touches a line passing through the origin.

Step 4

Use Distance Formula

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Answer

Using the distance formula and considering the geometry involved, the maximum distance can be found when the line from the origin to (1,1)(1, -1) is extended. The furthest point on the circle from the origin will be along this line, and we can use the Pythagorean theorem to evaluate the distance:

z=extdistance=2+extradius.|z| = ext{distance} = 2 + ext{radius}.

Therefore the maximum possible value of $|z| = 2 + ext{distance from origin to circle center} = 2 + ext{sqrt}(1^2 + (-1)^2) = 2 + ext{sqrt}(2) = 2 + ext{sqrt}(2).$$

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