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Consider the function $f(x) = \frac{e^x - 1}{e^x + 1}$ - HSC - SSCE Mathematics Extension 2 - Question 12 - 2017 - Paper 1

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Consider-the-function-$f(x)-=-\frac{e^x---1}{e^x-+-1}$-HSC-SSCE Mathematics Extension 2-Question 12-2017-Paper 1.png

Consider the function $f(x) = \frac{e^x - 1}{e^x + 1}$. (i) Show that $f(x)$ is increasing for all $x$. (ii) Show that $f(x)$ is an odd function. (iii) Describ... show full transcript

Worked Solution & Example Answer:Consider the function $f(x) = \frac{e^x - 1}{e^x + 1}$ - HSC - SSCE Mathematics Extension 2 - Question 12 - 2017 - Paper 1

Step 1

Given that the polynomial $P(x) = x^4 - 3x^3 + x^2 + 4$ has a factor $(x - a^2)$, find the value of $\alpha$

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Answer

To find α\alpha, we substitute x=a2x = a^2 in P(x)P(x):

P(a2)=(a2)43(a2)3+(a2)2+4=0P(a^2) = (a^2)^4 - 3(a^2)^3 + (a^2)^2 + 4 = 0

This leads to a algebraic expression depending on aa. Solve for α\alpha noting that specific roots will occur. The fundamental theorem will allow flexibilty in exposition and exhibiting relevant values and leads for comparison.

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