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The following proof aims to establish that -4 = 0 - HSC - SSCE Mathematics Extension 2 - Question 2 - 2022 - Paper 1

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The following proof aims to establish that -4 = 0. Let a = -4 ⇒ a² = 16 and 4a + 4 = -12 ⇒ a² + 4a + 4 = 4 ⇒ (a + 2)² = 2² ⇒ a + 2 = 2 ⇒ a = 0 At wh... show full transcript

Worked Solution & Example Answer:The following proof aims to establish that -4 = 0 - HSC - SSCE Mathematics Extension 2 - Question 2 - 2022 - Paper 1

Step 1

Line 1

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Answer

In Line 1, the assertion made is that If we let a=4a = -4, then it follows that this is a valid assignment. There is no implication error here because defining a variable is simply a statement.

Step 2

Line 2

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Answer

In Line 2, it states that a2=16a^2 = 16 and 4a+4=124a + 4 = -12. This is also a valid evaluation; however, we need to ensure that 4(4)+44(-4) + 4 equates to 12-12. Confirming this, we get 16+4=12-16 + 4 = -12, hence it is correct.

Step 3

Line 3

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Answer

In Line 3, a2+4a+4=4a^2 + 4a + 4 = 4 is rewritten correctly as (a+2)2=22(a + 2)² = 2². This is factually accurate; however, from our equivalence, it should result in a false statement given our prior definitions. Thus, this line is correctly derived but problematic based on prior definitions.

Step 4

Line 4

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Answer

In Line 4, a+2=2a + 2 = 2 implies a=0a = 0. This conclusion is incorrect because we initially assumed a=4a = -4. Therefore, the error occurs at this line, making Line 4 the incorrect implication.

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