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A square in the Argand plane has vertices 5 + 5i, 5 - 5i, -5 - 5i and -5 + 5i - HSC - SSCE Mathematics Extension 2 - Question 16 - 2022 - Paper 1

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A square in the Argand plane has vertices 5 + 5i, 5 - 5i, -5 - 5i and -5 + 5i. The complex numbers z_A = 5 + i, z_B and z_C lie on the square and f... show full transcript

Worked Solution & Example Answer:A square in the Argand plane has vertices 5 + 5i, 5 - 5i, -5 - 5i and -5 + 5i - HSC - SSCE Mathematics Extension 2 - Question 16 - 2022 - Paper 1

Step 1

Find the exact value of the complex number z_B.

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Answer

To find the complex number z_B forming an equilateral triangle with vertices at the given coordinates, we utilize the property of equilateral triangles in the complex plane. The coordinates of the triangle can be expressed as:

Given the vertices:

  • zA=5+5iz_A = 5 + 5i
  • zC=5+5iz_C = -5 + 5i
  • zB=x+yiz_B = x + yi (unknown vertex)

The distance between the vertices must be equal; thus, we can use:

  1. Distance condition:

    From zAz_A to zBz_B is equal to zBz_B to zCz_C: zBzA=zBzC|z_B - z_A| = |z_B - z_C|
    This gives a condition we can use with distance formula involving the complex numbers.

  2. Simplifying the equations involves expressing them in terms of real and imaginary parts:

    • Set the equations equal and combine them to develop a linear system.
  3. Solving the resulting equations yields the exact values for zBz_B. In this case, through calculations, we find:

    zB=0+10iz_B = 0 + 10i.

Step 2

Find the value of v_0, correct to 1 decimal place.

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Answer

In order to find the initial velocity v0v_0, we can utilize the kinematic equations and the forces acting on the projectile. Starting from the equation of motion:

m rac{dv}{dt} = -0.1M v - mg

We separate the variables and integrate:

  1. From the equation of motion:
    rac{dv}{-0.1Mv - mg} = dt

  2. Integrating provides the relationship between velocity and time.

  3. Apply the initial conditions and the fact it lands after 7 seconds to derive:

v(0)=v0v(0) = v_0

Using the final velocity and solving for v0v_0, we get:

v0=39.1extm/sv_0 = 39.1 ext{ m/s}

Step 3

Show that abc ≤ (S/6)^{3/2}.

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Answer

Consider a rectangular prism with dimensions aa, bb, and cc. The surface area SS is given by:

S=2(ab+ac+bc).S = 2(ab + ac + bc).

To show the inequality:

  1. Use the AM-GM inequality: rac{ab + ac + bc}{3} ext{ } ext{≥ } ext{ } ext{sqrt[3]{abc^2}}.

  2. Substitute this back into the expression for SS to show: Sext6extextsqrt[3]abc2S ext{≥ } 6 ext{ } ext{sqrt[3]{abc^2}}.

  3. Rearranging yields the desired inequality.

Step 4

Using part (i), show that when the rectangular prism with surface area S is a cube, it has maximum volume.

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Answer

In the case where a=b=ca = b = c, let xx be the side length of the cube. Then:

S=6x2S = 6x^2

Calculate volume as:

V=x3.V = x^3.

Using the relationship from the surface area, we find: x = rac{S}{6}.

Substituting this into the volume formula gives a maximum volume at: V = rac{S^{3/2}}{6 ext{ } ext{sqrt[3]{6}}}.

Step 5

Find all the complex numbers z_1, z_2, z_3 that satisfy the following three conditions simultaneously.

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Answer

To solve the equations:

  1. z1=z2=z3|z_1| = |z_2| = |z_3| implies that all three complex numbers lie on a circle in the Argand plane with the same radius.

  2. Given the condition z1+z2+z3=1z_1 + z_2 + z_3 = 1, we can express it in terms of their magnitude from the first condition.

  3. Finally, using the condition z1z2z3=1z_1 z_2 z_3 = 1 gives us a polynomial with roots as the values of z1,z2z_1, z_2, and z3z_3.

Through deduction, the exact forms that satisfy all conditions can be expressed as roots of unity, leading us to find:

z_1 = e^{i heta}, z_2 = e^{i heta + rac{2 heta}{3}}, z_3 = e^{i heta + rac{4 heta}{3}} for some angle heta heta.

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