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Question 16
A square in the Argand plane has vertices 5 + 5i, 5 - 5i, -5 - 5i and -5 + 5i. The complex numbers z_A = 5 + i, z_B and z_C lie on the square and f... show full transcript
Step 1
Answer
To find the complex number z_B forming an equilateral triangle with vertices at the given coordinates, we utilize the property of equilateral triangles in the complex plane. The coordinates of the triangle can be expressed as:
Given the vertices:
The distance between the vertices must be equal; thus, we can use:
Distance condition:
From to is equal to to :
This gives a condition we can use with distance formula involving the complex numbers.
Simplifying the equations involves expressing them in terms of real and imaginary parts:
Solving the resulting equations yields the exact values for . In this case, through calculations, we find:
.
Step 2
Answer
In order to find the initial velocity , we can utilize the kinematic equations and the forces acting on the projectile. Starting from the equation of motion:
m rac{dv}{dt} = -0.1M v - mg
We separate the variables and integrate:
From the equation of motion:
rac{dv}{-0.1Mv - mg} = dt
Integrating provides the relationship between velocity and time.
Apply the initial conditions and the fact it lands after 7 seconds to derive:
Using the final velocity and solving for , we get:
Step 3
Answer
Consider a rectangular prism with dimensions , , and . The surface area is given by:
To show the inequality:
Use the AM-GM inequality: rac{ab + ac + bc}{3} ext{ } ext{≥ } ext{ } ext{sqrt[3]{abc^2}}.
Substitute this back into the expression for to show: .
Rearranging yields the desired inequality.
Step 4
Answer
In the case where , let be the side length of the cube. Then:
Calculate volume as:
Using the relationship from the surface area, we find: x = rac{S}{6}.
Substituting this into the volume formula gives a maximum volume at: V = rac{S^{3/2}}{6 ext{ } ext{sqrt[3]{6}}}.
Step 5
Answer
To solve the equations:
implies that all three complex numbers lie on a circle in the Argand plane with the same radius.
Given the condition , we can express it in terms of their magnitude from the first condition.
Finally, using the condition gives us a polynomial with roots as the values of , and .
Through deduction, the exact forms that satisfy all conditions can be expressed as roots of unity, leading us to find:
z_1 = e^{i heta}, z_2 = e^{i heta + rac{2 heta}{3}}, z_3 = e^{i heta + rac{4 heta}{3}} for some angle .
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