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The complex number $z$ is chosen so that $1, z, z^2, \, \ldots, z^7$ form the vertices of the regular polygon shown - HSC - SSCE Mathematics Extension 2 - Question 1 - 2017 - Paper 1

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The-complex-number-$z$-is-chosen-so-that-$1,-z,-z^2,-\,-\ldots,-z^7$-form-the-vertices-of-the-regular-polygon-shown-HSC-SSCE Mathematics Extension 2-Question 1-2017-Paper 1.png

The complex number $z$ is chosen so that $1, z, z^2, \, \ldots, z^7$ form the vertices of the regular polygon shown. Which polynomial equation has all of these comp... show full transcript

Worked Solution & Example Answer:The complex number $z$ is chosen so that $1, z, z^2, \, \ldots, z^7$ form the vertices of the regular polygon shown - HSC - SSCE Mathematics Extension 2 - Question 1 - 2017 - Paper 1

Step 1

Determine the vertices of the polygon

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Answer

The complex numbers 1,z,z2,...,z71, z, z^2, ..., z^7 correspond to the vertices of a regular octagon in the complex plane, where each vertex can be represented as roots of unity.

Step 2

Identify the polynomial formed by these roots

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Answer

The roots are given by the equation: z81=0z^8 - 1 = 0 This polynomial represents all the 8th roots of unity.

Step 3

Match with provided options

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Answer

From the options provided, the polynomial that matches our derived polynomial is:

C. z81=0z^8 - 1 = 0.

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