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Let $ heta$ be the complex number satisfying $ar{ heta}^3 = 1$ and $ ext{Im}( heta) > 0$ - HSC - SSCE Mathematics Extension 2 - Question 6 - 2008 - Paper 1

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Let-$-heta$-be-the-complex-number-satisfying-$ar{-heta}^3-=-1$-and-$-ext{Im}(-heta)->-0$-HSC-SSCE Mathematics Extension 2-Question 6-2008-Paper 1.png

Let $ heta$ be the complex number satisfying $ar{ heta}^3 = 1$ and $ ext{Im}( heta) > 0$. The cubic polynomial, $p(z) = z^3 + az^2 + bz + c$, has zeros $1, - heta$ ... show full transcript

Worked Solution & Example Answer:Let $ heta$ be the complex number satisfying $ar{ heta}^3 = 1$ and $ ext{Im}( heta) > 0$ - HSC - SSCE Mathematics Extension 2 - Question 6 - 2008 - Paper 1

Step 1

Find $p(z)$

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Answer

To find the cubic polynomial p(z)p(z) with given roots, we can use Vieta's formulas. The polynomial can be expressed as:

p(z) = (z - 1)(z + heta)(z + ar{ heta})

Expanding this, we first notice that:

egin{align*} (z + heta)(z + ar{ heta}) &= z^2 + ( heta + ar{ heta})z + heta ar{ heta}
&= z^2 - 2 ext{Re}( heta)z + | heta|^2
&= z^2 - 2 ext{Re}( heta)z + 1 ext{ (assuming } | heta| = 1) ext{ (since } heta = e^{i heta}) ext{)} ext{)}

Thus,

So, combining with $(z - 1)$ gives us: $$p(z) = (z - 1)(z^2 - 2 ext{Re}( heta)z + 1)$$ When simplified, we will match the coefficients to find $a$, $b$, and $c$.

Step 2

Show that the line $ ext{l}$ has equation $bx ext{ sec } heta - ay an heta - ab = 0$

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To find the equation of the tangent line at point PP:

  1. Differentiate the hyperbola equation to find the slope at PP.
  2. Use the point-slope form of the line equation.
  3. By substituting the coordinates of point PP, we derive the equation to be:

bxextsechetaayanhetaab=0bx ext{ sec } heta - ay an heta - ab = 0.

Step 3

Show that $SR = rac{ab( ext{sec } heta - 1)}{ rac{1}{ an^2 heta} + b^2 ext{sec}^2 heta}$

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To show the length of segment SRSR:

  1. Apply the Pythagorean theorem.
  2. Use trigonometric identities to express the distances in terms of aa, bb, and heta heta.
  3. Simplify to arrive at:

SR = rac{ab( ext{sec } heta - 1)}{ rac{1}{ an^2 heta} + b^2 ext{sec}^2 heta}.

Step 4

Show that $SR imes S'R' = b^2$

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To demonstrate this relation, we apply the properties of the hyperbola and the lengths calculated before:

  1. Express both SRSR and SRS'R' in terms of bb and simplify.
  2. Verify the product results in b2b^2.

Step 5

Show that $ rac{1}{r} - rac{r-1}{r} = rac{1}{n}$

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Answer

To prove this identity:

  1. Start with the left-hand side: rac{1}{r} - rac{r-1}{r} = rac{-1}{r}
  2. Rearranging gives rac{1}{n}. Thus proving the equality.

Step 6

Show that the sum $ rac{1}{r} + rac{1}{r} + rac{1}{m} - rac{1}{r} = rac{1}{n}$

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To demonstrate this:

  1. Simplify the left-hand side by adding values.
  2. After rearranging, you end up with the relationship:

rac{1}{n}.

Step 7

What is the limiting value of the sum $ rac{1}{inom{m}{n}}$ as $m$ increases without bound?

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As mm increases:

  1. The term rac{1}{inom{m}{n}} approaches 00 when considering the growth of binomial coefficients for large mm. Therefore, the limiting value is 00.

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