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Which of the following is a vector equation of the line joining the points A(4, 2, 5) and B(-2, 2, 1)? A - HSC - SSCE Mathematics Extension 2 - Question 3 - 2021 - Paper 1

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Which-of-the-following-is-a-vector-equation-of-the-line-joining-the-points-A(4,-2,-5)-and-B(-2,-2,-1)?--A-HSC-SSCE Mathematics Extension 2-Question 3-2021-Paper 1.png

Which of the following is a vector equation of the line joining the points A(4, 2, 5) and B(-2, 2, 1)? A. \( \mathbf{r} = \begin{pmatrix} 4 \ 2 \ 5 \end{pmatrix} + ... show full transcript

Worked Solution & Example Answer:Which of the following is a vector equation of the line joining the points A(4, 2, 5) and B(-2, 2, 1)? A - HSC - SSCE Mathematics Extension 2 - Question 3 - 2021 - Paper 1

Step 1

Determine the direction vector between points A and B

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Answer

To find the direction vector between the points A(4, 2, 5) and B(-2, 2, 1), we subtract the coordinates of point A from point B.

Direction vector ( \mathbf{d} = B - A = \begin{pmatrix} -2 - 4 \ 2 - 2 \ 1 - 5 \end{pmatrix} = \begin{pmatrix} -6 \ 0 \ -4 \end{pmatrix} .

Step 2

Form the vector equation of the line

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Answer

Using the point A as the initial position vector and ( \lambda ) as the parameter, the vector equation of the line can be expressed as: ( \mathbf{r} = \begin{pmatrix} 4 \ 2 \ 5 \end{pmatrix} + \lambda \begin{pmatrix} -6 \ 0 \ -4 \end{pmatrix} ).

To compare with the given options, we notice that we can express the direction vector in a different way for simpler representation. Reordering can lead us to use integers that represent the direction effectively.

Thus, we will factor out common elements or correctly represent this using chosen multiples as necessary.

Step 3

Identify the correct option

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Answer

Upon analyzing the options, we can see that option B presents a different form consistent with the direction vector found, specifically by adjusting the vector to match a valid common direction.

Thus, the correct answer is Option B: ( \mathbf{r} = \begin{pmatrix} 4 \ 2 \end{pmatrix} + \lambda \begin{pmatrix} 0 \ 3 \end{pmatrix} ).

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