Suppose $f(x)$ is a differentiable function such that
$$\frac{f(a)+f(b)}{2} \geq f\left( \frac{a+b}{2} \right)$$ for all $a$ and $b$ - HSC - SSCE Mathematics Extension 2 - Question 10 - 2017 - Paper 1
Question 10
Suppose $f(x)$ is a differentiable function such that
$$\frac{f(a)+f(b)}{2} \geq f\left( \frac{a+b}{2} \right)$$ for all $a$ and $b$.
Which statement is always true... show full transcript
Worked Solution & Example Answer:Suppose $f(x)$ is a differentiable function such that
$$\frac{f(a)+f(b)}{2} \geq f\left( \frac{a+b}{2} \right)$$ for all $a$ and $b$ - HSC - SSCE Mathematics Extension 2 - Question 10 - 2017 - Paper 1
Step 1
A. $\int_0^1 f(x)dx \geq \frac{f(0)+f(1)}{2}$
96%
114 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
This statement cannot be guaranteed to always be true, as it depends on the specific function f(x).
Step 2
B. $\int_0^1 f(x)dx \leq \frac{f(0)+f(1)}{2}$
99%
104 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
This statement is indeed always true based on the given condition. The inequality suggests the function is concave up, which leads to this conclusion through Jensen's inequality.
Step 3
C. $f'\left( \frac{1}{2} \right) \geq 0$
96%
101 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
This statement cannot be established as a certainty without additional information about the function f(x).
Step 4
D. $f'\left( \frac{1}{2} \right) \leq 0$
98%
120 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
Similar to statement C, this cannot be determined to always be true without further context.