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Suppose $f(x)$ is a differentiable function such that $$\frac{f(a)+f(b)}{2} \geq f\left( \frac{a+b}{2} \right)$$ for all $a$ and $b$ - HSC - SSCE Mathematics Extension 2 - Question 10 - 2017 - Paper 1

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Suppose-$f(x)$-is-a-differentiable-function-such-that-$$\frac{f(a)+f(b)}{2}-\geq-f\left(-\frac{a+b}{2}-\right)$$-for-all-$a$-and-$b$-HSC-SSCE Mathematics Extension 2-Question 10-2017-Paper 1.png

Suppose $f(x)$ is a differentiable function such that $$\frac{f(a)+f(b)}{2} \geq f\left( \frac{a+b}{2} \right)$$ for all $a$ and $b$. Which statement is always true... show full transcript

Worked Solution & Example Answer:Suppose $f(x)$ is a differentiable function such that $$\frac{f(a)+f(b)}{2} \geq f\left( \frac{a+b}{2} \right)$$ for all $a$ and $b$ - HSC - SSCE Mathematics Extension 2 - Question 10 - 2017 - Paper 1

Step 1

A. $\int_0^1 f(x)dx \geq \frac{f(0)+f(1)}{2}$

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Answer

This statement cannot be guaranteed to always be true, as it depends on the specific function f(x)f(x).

Step 2

B. $\int_0^1 f(x)dx \leq \frac{f(0)+f(1)}{2}$

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Answer

This statement is indeed always true based on the given condition. The inequality suggests the function is concave up, which leads to this conclusion through Jensen's inequality.

Step 3

C. $f'\left( \frac{1}{2} \right) \geq 0$

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Answer

This statement cannot be established as a certainty without additional information about the function f(x)f(x).

Step 4

D. $f'\left( \frac{1}{2} \right) \leq 0$

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Answer

Similar to statement C, this cannot be determined to always be true without further context.

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