There are two tanks on a property, Tank A and Tank B - HSC - SSCE Mathematics Standard - Question 24 - 2020 - Paper 1
Question 24
There are two tanks on a property, Tank A and Tank B. Initially, Tank A holds 1000 litres of water and Tank B is empty.
(a) Tank A begins to lose water at a constan... show full transcript
Worked Solution & Example Answer:There are two tanks on a property, Tank A and Tank B - HSC - SSCE Mathematics Standard - Question 24 - 2020 - Paper 1
Step 1
a) Draw the graph of Tank A
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Answer
To draw the graph of Tank A, we can use the equation V=1000−20t. This means that for each minute that passes, 20 litres are lost from the initial 1000 litres.
At t=0, V=1000 litres.
At t=10, V=800 litres.
At t=20, V=600 litres.
At t=25, V=500 litres.
At t=50, V=0 litres (the tank would be empty).
Plot these points on the graph and connect them to show a straight line decreasing from (0, 1000) to (50, 0). Label this line as 'Tank A'.
Step 2
b) Find the value of $t$ when tanks are the same volume
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Answer
Tank B starts filling at t=15 minutes.
From t=15, the volume of Tank B can be calculated as VB=30(t−15) once it starts filling.
To find when both tanks are equal, set the equations equal: 1000−20t=30(t−15).
Rearranging gives:
1000 - 20t = 30t - 450
1450 = 50t
t = rac{1450}{50} = 29.
The two tanks contain the same volume at t=29 minutes.
Step 3
c) Find $t$ when total volume is 1000 litres
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Answer
To find when the total volume in both tanks is 1000 litres:
The total volume is VA+VB=1000 litres.
From part (a), VA=1000−20t and from part (b), VB=30(t−15) for textext15.
Setting up the equation:
(1000 - 20t) + 30(t - 15) = 1000
Simplifying:
1000 - 20t + 30t - 450 = 1000
10t - 450 = 0
t = 45.
At t=45 minutes, the total volume of water in the two tanks is 1000 litres.