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José takes out a loan of $9000 - HSC - SSCE Mathematics Standard - Question 13 - 2024 - Paper 1

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José takes out a loan of $9000. Simple interest is charged on the loan. The loan and the interest charged will be repaid by making monthly repayments of $300 over 4... show full transcript

Worked Solution & Example Answer:José takes out a loan of $9000 - HSC - SSCE Mathematics Standard - Question 13 - 2024 - Paper 1

Step 1

Calculate the Total Repayment

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Answer

The total repayment can be computed as follows:

Since José makes monthly repayments of $300 for 4 years, the total number of payments is: 4 years×12 months/year=48 months4 \text{ years} \times 12 \text{ months/year} = 48 \text{ months}.

Thus, the total repayment is: 300 dollars/month×48 months=14400 dollars300 \text{ dollars/month} \times 48 \text{ months} = 14400 \text{ dollars}.

Step 2

Calculate the Total Interest Paid

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Answer

The total interest paid is the total repayment minus the original loan amount:

Total Interest=14400 dollars9000 dollars=5400 dollars\text{Total Interest} = 14400 \text{ dollars} - 9000 \text{ dollars} = 5400 \text{ dollars}.

Step 3

Calculate the Simple Interest Rate

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Answer

The simple interest formula is given by: I=P×r×tI = P \times r \times t, where:

  • II is the interest paid,
  • PP is the principal amount (the loan),
  • rr is the interest rate,
  • tt is the time (in years).

Rearranging the formula to find the interest rate rr gives us: r=IP×tr = \frac{I}{P \times t}.

Plugging in the values: r=54009000×4=540036000=0.15r = \frac{5400}{9000 \times 4} = \frac{5400}{36000} = 0.15.

Thus, to convert this into a percentage: r×100=15%r \times 100 = 15\%.

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