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Chris opens a bank account and deposits $1000 into it - HSC - SSCE Mathematics Standard - Question 3 - 2019 - Paper 1

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Chris opens a bank account and deposits $1000 into it. Interest is paid at 3.5% per annum, compounding annually. Assuming no further deposits or withdrawals are mad... show full transcript

Worked Solution & Example Answer:Chris opens a bank account and deposits $1000 into it - HSC - SSCE Mathematics Standard - Question 3 - 2019 - Paper 1

Step 1

Calculate the balance after the first year

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Answer

To find the balance at the end of the first year, we use the formula for compound interest:

A=P(1+r)tA = P(1 + r)^t

Where:

  • AA is the amount of money accumulated after n years, including interest.
  • PP is the principal amount (the initial deposit, which is $1000).
  • rr is the annual interest rate (decimal).
  • tt is the number of years the money is invested or borrowed.

For the first year:

  • P=1000P = 1000
  • r=0.035r = 0.035
  • t=1t = 1

Substituting in the values: A=1000(1+0.035)1=1000(1.035)=1035A = 1000(1 + 0.035)^1 = 1000(1.035) = 1035

So, the balance after the first year is $1035.00.

Step 2

Calculate the balance after the second year

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Answer

For the second year, we apply the same formula using the new principal amount, which is now $1035.

A=1035(1+0.035)1=1035(1.035)=1071.225A = 1035(1 + 0.035)^1 = 1035(1.035) = 1071.225

Thus, the balance at the end of the second year is approximately $1071.23.

Step 3

Final answer

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Answer

The balance in the account at the end of two years will be $1071.23, which corresponds to option B.

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