Consider the diagram below - HSC - SSCE Mathematics Standard - Question 14 - 2021 - Paper 1

Question 14

Consider the diagram below.
N
|
|
A
|
| 25°
|
B --- E
What is the true bearing of A from B?
A. 025°
B. 065°
C. 115°
D. 295°
Worked Solution & Example Answer:Consider the diagram below - HSC - SSCE Mathematics Standard - Question 14 - 2021 - Paper 1
What is the true bearing of A from B?

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To determine the true bearing of point A from point B, we first recognize that bearings are measured clockwise from the North direction.
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From the diagram, point A is at a 25° angle from the North towards the East (E). This forms a clockwise angle from North to the line AB.
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Next, to find the bearing from point B to point A, we need to calculate the angle moving clockwise from point N through points E and then to point B.
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The bearing can thus be calculated as:
extBearingfromBtoA=360°−25°=335°
However, since we are looking for the bearing from A to B, we take:
extBearingfromAtoB=360°−335°=25°
-
Therefore, the true bearing of A from B is:
- D. 295° (which is obtained by measuring the angle clockwise around back to the North direction from point A's position.)
Thus, the correct answer is option D: 295°.
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